Answer:
The wife gets £468 over the son
Step-by-step explanation:
Firstly, we shall calculate the total amount Brian made from from what he and Paul won.
The ratio is 1:4, meaning for every 2 part Brain takes, Paul takes 4
Paul’s share is thus 1/5 * 7800 = 7800/5 = £1560
Now we have another ratio for sharing the amount Brain has at home.
The total ratio here is 1+6+3 = 10
The share of the wife will be 6/10 * 1560 = 6 * 156 = 936
The son share is half of this which is 936/2 = 468
The difference between their shares is £936-£468 = £468
I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,
So, 
So, 
Hope this helps you!
Answer:
Since 10/9 is greater than 1, multiplying by 10/9 makes the value larger
Step-by-step explanation:
Step 1: Solve the fraction
10/9 = 1.1112
Therefore 10/9 > 1
Step 2: Multiple the fraction by itself
10/9 x 10/9 = 100/81
Convert fraction to decimals
100/81 = 1.2345678901.....
1.234567901 > 1.1112
Therefore 10/9 x 10/9 is bigger than 10/9
Answer:
A would be the line of best fit and B would be the oulier
Hey there,
Your question states: <span>A store charges $2.10 for a medium bag of fruit slices. Assuming that the rate stays the same, how much should the store charge for a large bag of the slices?
So sense this is a medium bad of fruit slices, we would divide 2.10 by 2.
Your answer would be 1.5 Now, all we do is we add 2.10+1.5 and we get 3.15. The reason would be because sense we now know the price of the size of it being small, we just add that size on top of the medium size to get 3.15.
Hope this helps.
~Jurgen</span>
