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Agata [3.3K]
2 years ago
10

In a sale the price of lawnmowers are decreased by 16% Jude buys a lawnmower in the sale for £369.60 how much was the lawnmower

before the sale
Mathematics
1 answer:
Stella [2.4K]2 years ago
8 0

Answer:

Step-by-step explanation:

Jude paid 84% of the original price. That comes about because 369.60 is the price he paid which includes as 16% reduction.

84/100 * x = 369.60              Multiply by 100

84x = 36960                         Divide by 84

84/84 x = 36960/84

x = 440

So the original price was 440 pounds

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Step-by-step explanation:

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What is the area of this figure?​
lesantik [10]

Answer:

\Huge\boxed {A =859ft^{2} }

Step-by-step explanation:

Hello There!

To solve for the area of this figure we need to split the figure into 3 different parts:

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a rectangle with a width of 9ft + 7ft and a length of 25 ft

a rectangle with a width of 18 ft and a length of 22 ft

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1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera
Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}

SP \approx 8.246

PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}

PA \approx  8.246

AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}

AZ \approx 8.246

ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}

ZS \approx 8.246

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

m_{SA} = \frac{6-(-4)}{6-(-4)}

m_{SA} = 1

m_{PZ} = \frac{4-(-2)}{-2-4}

m_{PZ} = -1

Since m_{SA}\cdot m_{PZ} = -1, diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)

M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)

M_{SA} = (-2,-2)+(3,3)

M_{SA} = (1,1)

M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)

M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)

M_{PZ} = (2,-1)+(-1,2)

M_{PZ} = (1,1)

Then, the diagonals SA and PZ bisect each other.

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