What is the length of the shortest altitude in a triangle, if the lengths of the sides are 24 cm, 25 cm, 7 cm?
1 answer:
Answer:
The shortest altitude is 6.72 cm
Step-by-step explanation:
Given that the side lengths are
24 cm, 25 cm, 7 cm
The area of a triangle =
Where;
s = Half the perimeter = (24 + 25 + 7)/2 = 28
A = √((28×(28 - 24)×(28 - 25)×(28 - 7)) = 84 cm²
We note that 84/7 = 12
Therefore, the triangle is a right triangle with hypotenuse = 25, and legs, 24 and 7, the height of the triangle = 7
To find the shortest altitude, we utilize the formula for the area of the triangle A = 1/2 base × Altitude
Altitude = A/(1/2 ×base)
Therefore, the altitude is inversely proportional to the base, and to reduce the altitude, we increase the base as follows;
We set the base to 25 cm to get;
Area of the triangle A = 1/2 × base × Altitude
84 = 1/2 × 25 × Altitude
Altitude = 84/(1/2 × 25) = 6.72 cm
The shortest altitude = 6.72 cm.
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Answer:
We conclude that this is an unusually high number of faulty modems.
Step-by-step explanation:
We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.
The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.
Let p = <em><u>population proportion</u></em>.
So, Null Hypothesis, : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}
Alternate Hypothesis, : p > 0.013 {means that this is an unusually high number of faulty modems}
The test statistics that would be used here <u>One-sample z-test</u> for proportions;
T.S. = ~ N(0,1)
where, = sample proportion faulty modems=
= 0.027
n = sample of modems = 367
So, <u><em>the test statistics</em></u> =
= 2.367
The value of z-test statistics is 2.367.
Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>
Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.
Therefore, we conclude that this is an unusually high number of faulty modems.