Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Answer:
(0, 2)
Step-by-step explanation:
add 5 to -5 and -3
Answer:
lesser x is 1
greater x is 3
Step-by-step explanation:
Here, we want to solve the equation so as to get the bigger and the lesser x values
We proceed as follows;
x^2 -4x + 3 = 0
x^2 - x-3x + 3 = 0
x(x-1) -3(x-1) = 0
(x-3)(x-1) = 0
x = 3
or x = 1
Greater x is 3
lesser x is 1
1 toy costs $3 ( $3 x 1 = $3)<span>
2 toys cost $6 ( </span> $3 x 2 = $6)<span>
3 toys cost $9 </span>( $3 x 3 = $9)
4 toys cost $12 ( $3 x 4 = $12)
answer 4 toys will cost $12
