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Andreas93 [3]
3 years ago
10

$100 is invested at 12% per year. If the amount is compounded annually, write the total amount after 2 years in exponential func

tion form.
Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

A = $100(1.12)^2

Step-by-step explanation:

The standard formula for compound interest is given as;

A = P(1+r/n)^(nt) .....1

Where;

A = final amount/value

P = initial amount/value (principal)

r = rate yearly

n = number of times compounded yearly.

t = time of investment in years

For this case;

P = $100

t = 2years

n = 1

r = 12% = 0.12

Substituting the values, we have;

A = $100(1+0.12)^(2)

A = $100(1.12)^2

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g A psychic was tested for extrasensory perception (ESP). The psychic was presented with cards face down and asked to determine
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Answer:

Step-by-step explanation:

Hello!

The objective is to test ESP, for this, a psychic was presented with cards face down and asked to determine if each of the cards was one of four symbols: a star, cross, circle, square.

Be X: number of times the psychic identifies the symbols on the cards correctly is a size n sample.

p the probability that the psychic identified the symbol on the cards correctly

You have to calculate the sample size n to estimate the proportion with a confidence level of 95% and a margin of error of d=0.01

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Every time the psychic has to identify a card he can make two choices:

"Success" he identifies the card correctly

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Let's say, for example, that the card has the star symbol.

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And the probability of not identifying it correctly will be P(failure)= P(cross) + P(circle) + P(square)= 1/4 + 1/4 + 1/4= 3/4= 0.75

So for this experiment, we'll assume the "worst case scenario" and use p'= 1/4 as the estimated probability of the psychic identifying the symbol on the card correctly.

The value of Z will be Z_{1-\alpha /2}= Z_{0.975}= 1.96

Now using the formula you have to clear the sample size:

d= Z_{1-\alpha /2} * (\sqrt{\frac{p'(1-p')}{n} } )

\frac{d}{Z_{1-\alpha /2}} = \sqrt{\frac{p'(1-p')}{n} }

(\frac{d}{Z_{1-\alpha /2}})^2 =\frac{p'(1-p')}{n}

n*(\frac{d}{Z_{1-\alpha /2}})^2 = p'(1-p')

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To estimate p with a margin of error of 0.01 and a 95% confidence level you have to take a sample of 7203 cards.

I hope this helps!

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