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2 years ago

11

Which graph shows a function and its inverse?

1 answer:

Hunter-Best [27]2 years ago

8 0

very simple it's b. tell me if you need help with anything els

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sergij07 [2.7K]

Answer:

I pretty sure the answer is 32.8 miles per hour

Hope this helps!

6 0

3 years ago

State the horizontal asymptote of the rational function. f(x) = quantity x squared plus three x minus two divided by quantity x

omeli [17]

$f(x)=\dfrac{x^2+3x-2}{x-2}\\ D_f=\mathbb{R}\setminus\{2\}\\\\ \displaystyle \lim_{x\to \infty}\dfrac{x^2+3x-2}{x-2}=\lim_{x\to \infty}\dfrac{x\left(x+3-\dfrac{2}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}=\lim_{x\to \infty}\dfrac{x+3-\dfrac{2}{x}}{1-\dfrac{2}{x}}=\dfrac{\infty}{1}=\infty\\ \lim_{x\to -\infty}\dfrac{x^2+3x-2}{x-2}=\lim_{x\to -\infty}\dfrac{x\left(x+3-\dfrac{2}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}=\lim_{x\to -\infty}\dfrac{x+3-\dfrac{2}{x}}{1-\dfrac{2}{x}}=\dfrac{-\infty}{1}=-\infty$

The limits are not numbers, so the asymptote doesn't exist.

8 0

3 years ago

15f) Determine the line of symmetry. y = x2+16x+64

Slav-nsk [51]

Answer:

x=-8

Step-by-step explanation:

the equation is in standard form of y=ax^2+bx+c

so, to find the vertex, or axis of symmetry do -b/2a.

-16/2(1)=

-8

7 0

3 years ago

Every _____ tessellates decagon, octagon, pentagon, triangle

Nookie1986 [14]

Well.. I know the definition of tessellates can help us figure out the answer..

<span>A tessellation of a flat surface is the tiling of a plane using one or more geometric shapes, called tiles, with no overlaps and no gaps.</span>

<span>I know we can do this with triangles. </span>

<span>My guess would be triangles.</span>

<span>
</span>

<span>Good Luck! <3</span>

7 0

3 years ago

Read 2 more answers

Is -2t^2+3t+4 in standard form

Paul [167]

Answer:

$-2t^2+3t+4$ or $-2t^2+3t^1+4t^0$

Step-by-step explanation:

The equation is already written in standard form.

You write the largest exponents to the left and the smallest to the right.

<u>Your expression: </u> $-2t^2+3t+4$ <u> can also be expressed as this below:</u>

$-2t^2+3t^1+4t^0$

t to the first power means mutiplying by t

t to the 0 power mean mutiplying by 1 or basically you get the same result

If t was 2...

$3t= 3(2)=6\\3t^1=3(2)^1=3(2)=6$

Same result:

$4=4\\4t^0=4(2)^0=4(1)=4\\$

8 0

4 years ago