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VladimirAG [237]
3 years ago
11

I NEED HELP ASAP

Mathematics
1 answer:
deff fn [24]3 years ago
5 0

For the first question you need to find the formula for the rectangle, after you did that fill it in. and find your answer.

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Mr. Duncan bought a table at a discount if 30% thus saving $42. what was the marked price of the table?​
katovenus [111]

Answer:

$140

Step-by-step explanation:

if 30% of full price = $42 then 100% = 42/0.3 = 140

5 0
3 years ago
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Find the quotient. 64,705 divided by 386
goldfiish [28.3K]

Answer:

167 243/386

Step-by-step explanation:

For steps, use this link:

https://mathsolver.microsoft.com/en/solve-problem/64705%20%60div%20%20386

6 0
2 years ago
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Will mark brainiest btw if I fail this I fail math pls no guessing
lesya [120]

Answer:

72 is the least common multiple

Step-by-step explanation:

The first one is the multiples of 9 and the second one is of 8

The only one they have in common is the number 72

7 0
3 years ago
If the price of a purse increased from $45 to $54, what was the percent of increase
Marrrta [24]
If you set it up in cross multiplication then you would have (x/100 = 45/54) then cross multiply so then i would look like this (54x/4,500) so from there you would divide 54 from 4,500 i hope this helps in any way  oh and it should come up to be 83.3333333 which would be 83% lol
5 0
3 years ago
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A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?
skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

From the three diagrams, we can deduce the sample space S set as follows

          S={(H,H),(H,T),(T,H),(T,T)}

with n(S)=4 where n(S) is the number of elements in the set S

tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

          E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

          P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

Event E " tossing a coin twice and getting a tail in each toss " may be considered as two events

Event A " toss a coin once and get a tail " and event B "toss the coin a second time and get a tail "

with the probabilities of each event A and B given by

          P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

        P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

8 0
3 years ago
Read 2 more answers
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