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VladimirAG [237]
3 years ago
11

I NEED HELP ASAP

Mathematics
1 answer:
deff fn [24]3 years ago
5 0

For the first question you need to find the formula for the rectangle, after you did that fill it in. and find your answer.

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I Need Help Like Now!!
kogti [31]

Answer:

\frac{136}{999}

Step-by-step explanation:

We require 2 equations with the repeating decimal after the decimal point in both equations.

The bar above 136 indicates that 136 is being repeated

let x = 0.136136...... → (1) Multiply both sides by 1000

1000x = 136.136.... → (2)

Subtract (1) from (2) to eliminate the decimal part

999x = 136 ( divide both sides by 999 )

x = \frac{136}{999}

5 0
3 years ago
(3x + 10) (2x + 15) what is the value of x ?
Mars2501 [29]
Answer:
6x^2 + 65x + 150

Explanation:

(3x+10)(2x+15)
6x^2 + 45x + 20x + 150
6x^2 + 65x + 150
5 0
3 years ago
A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?
skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

From the three diagrams, we can deduce the sample space S set as follows

          S={(H,H),(H,T),(T,H),(T,T)}

with n(S)=4 where n(S) is the number of elements in the set S

tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

          E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

          P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

Event E " tossing a coin twice and getting a tail in each toss " may be considered as two events

Event A " toss a coin once and get a tail " and event B "toss the coin a second time and get a tail "

with the probabilities of each event A and B given by

          P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

        P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

8 0
2 years ago
Read 2 more answers
Each pair of points lies on a line with the given slope. Find x.
Gwar [14]

Answer:

the answer is -2 inorder to get -1 slope

8 0
3 years ago
Solve the equation 4^3x+2=3
const2013 [10]

Answer:

Exact Form:

x = 1/64

Decimal Form:

x  = 0.015625

Step-by-step explanation:

4 0
3 years ago
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