Answer:
Na+-0.0648M
SO4²-0.1352M
Explanation:
First find the R.A.M of the sodium sulphate
(23×2)+(32)+(16×4)=142
Find the portion of sodium ions=46/142×0.2
=0.0648M
Sulphate=
0.2-0.0648=0.1352M
We are given the balanced equation 2NaF + Ca10(PO4)6(OH)2 → Ca10(PO4)6F2 + 2NaOH. The fluorapatite is the product together with sodium hydroxide. The ions involved are (PO4) 3-, Ca 2+ and <span>F-. We add the charges and check if the sum is zero, 2*10+-3*6+-1*2 =0. the zero sum tells that the compound has zero charge or neutral</span>
Answer:
I don't know how to get the answer sorry
Explanation:
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