All categories

2 years ago

Calculate the number of oxygen atoms in a 80.0 g sample of scheelite (CaWo).

Chemistry

1 answer:

castortr0y [4]2 years ago

3 0

Answer:

Explanation:

scheelite is CaWO₄

Mol weight = 288

80 g of scheelite = 80 / 288 = 27.77 x 10⁻² moles

27.77 x 10⁻² moles of scheelite = 27.77 x 10⁻² x 6.02 x 10²³ molecules of scheelite

= 167.17 x 10²¹ molecules of scheelite

1 molecule of scheelite contains 4 atoms of oxygen

167.77 x 10²¹ molecules of scheelite contains 4 x 167.77 x 10²¹ atoms of oxygen .

= 671.08 x 10²¹ atoms of oxygen .

= 671 x 10²¹ atoms .

You might be interested in

The particles in the most solids are arranged in a regular pattern.

borishaifa [10]

True because solids are colder so the particles are in a fixed pattern that join them into a regular pattern

5 0

3 years ago

What happens in this reaction and why? hept-3-yne + Br2 -->

maw [93]

Here we have to explain and predict the product of the reaction between hept-3-yne and bromine (Br₂)

The reaction between hept-3-yne and bromine produces trans-3,4-dibromo-3-heptene.

The reaction between the unsaturated hydrocarbon with halogen remove the unsaturation in the molecule and produces di halo compound. The reaction proceed through the formation of bromonium ion.

In this reaction as the unsaturation present in the middle of the alkyl chain i.e. hept-3-yne. The reaction will stop after the formation of di-halo compound with one double bond as shown in the figure.

The product will be exclusively trans product as the bromine is a bulky group and the formation of bromonium ion (intermediate) will be one side of the unsaturated compound.

6 0

3 years ago

Which describes interactions between substances and stomata during photosynthesis?

Mariulka [41]

The interaction between the substances and stomata is a chemical reaction, light energy strikes at the chlorophyll molecules, whose electrons gets excited to a state of higher energy, and they come back to their state of lower energy by emission of energy, which is accepted by a chain of acceptors, and energy is generated.

8 0

3 years ago

What role does the oxidizing agent play in a redox reaction

kvv77 [185]

The oxidizing agent receives electrons from the reducing agent. 2) The oxidation agent takes electrons from the reducing agent.

3 0

2 years ago

Read 2 more answers

If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?

Semenov [28]

Answer:

see explanation below

Explanation:

The question is incomplete. Here's the complete question:

Consider the following reaction: 

SO2Cl2 -----> SO2(g) + Cl2(g) 

Kc= 2.99 x 10^-7 at 227 degrees celcius 

If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?

This is a problem of equilibrium, therefore, we need to solve this using the expression of equilibrium constant. To do that, we need to wirte an ICE chart and solve from there:

SOCl2 ---------> SO2 + Cl2 Kc = 2.99x10⁻⁷

i) 0.168 0 0

c) -x +x +x

e) 0.168-x x x

Writting the Kc expression:

Kc = [SO2] [Cl2] / [SOCl2]

Replacing the values from the chart:

2.99x10⁻⁷ = x² / 0.168 - x

However, Kc is a very very small value, therefore, we can assume that the value of "x" would be very small too, and we can neglect the 0.168-x and just round it to 0.168:

2.99x10⁻⁷ = x²/0.168

2.99x10⁻⁷ * 0.168 = x²

√5.02x10⁻⁸ = x

x = 2.24x10⁻⁴ M

This means then, that the concentration of Cl2 in equilibrium would be:

[Cl₂] = 2.24x10⁻⁴ M

5 0

3 years ago