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3 years ago

Calculate the number of oxygen atoms in a 80.0 g sample of scheelite (CaWo).

Chemistry

1 answer:

castortr0y [4]3 years ago

3 0

Answer:

Explanation:

scheelite is CaWO₄

Mol weight = 288

80 g of scheelite = 80 / 288 = 27.77 x 10⁻² moles

27.77 x 10⁻² moles of scheelite = 27.77 x 10⁻² x 6.02 x 10²³ molecules of scheelite

= 167.17 x 10²¹ molecules of scheelite

1 molecule of scheelite contains 4 atoms of oxygen

167.77 x 10²¹ molecules of scheelite contains 4 x 167.77 x 10²¹ atoms of oxygen .

= 671.08 x 10²¹ atoms of oxygen .

= 671 x 10²¹ atoms .

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Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

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3 years ago