Question

What volume of 0.0105-M HBr solution is be required to titrate 125 mL of a 0.0100-M Ca(OH)2 solution?

Answer 1

Answer: The volume of HBr solution comes out to be 238.1 mL

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HBr$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.0105M\\V_1=?mL\\n_2=2\\M_2=0.010M\\V_2=125mL$

Putting values in above equation, we get:

$1\times 0.0105\times V_1=2\times 0.010\times 125\\\\V_1=238.1mL$

Hence, the volume of HBr solution comes out to be 238.1 mL