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ki77a [65]
3 years ago
13

What was the cost of the family's clothing in 1991?

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

Answer:

B.

Step-by-step explanation:

Assuming the cost increased linearly is equivalent to assuming the cost increased at a constant rate. Because the cost of the clothing increased from $620 to $1,000 in 10 years, the constant rate is equal to

= ($1,000 - $620)/10

= $38 per year

Therefore, the cost of the family’s clothing in 1991 (6 years after 1985) is:

$620 + (6 years)($38 per year)

= $620 + $228

= $848

Olegator [25]3 years ago
5 0

Answer:

B. 848

Step-by-step explanation:

Hope it helps :>

Naosjsjwowiajajaiaoaoaoao

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Ben needs to buy orange juice he can buy 64 fl oz at the grocery store for $2.00 or he can buy 256 fl oz at the whole sale for $
Sholpan [36]
1.    2.00/64=3.125 cents per oz 
2.    7.50/256=2.930 cents per oz.
3.    The best deal is at the whole sale 
8 0
3 years ago
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
The volume of a cone =13πr2h
xz_007 [3.2K]

Answer:

Volume of cone = 418.67 cm³ (Approx.)

Step-by-step explanation:

Given:

Radius of cone = 5 cm

Height of cone = 16 cm

Find:

Volume of cone

Computation:

Volume of cone = [1/3][π][r²][h]

Volume of cone = [1/3][3.14][5²][16]

Volume of cone = [1/3][3.14][25][16]

Volume of cone = [1/3][3.14][400]

Volume of cone = [1/3][1,256]

Volume of cone = 418.67 cm³ (Approx.)

8 0
3 years ago
Which experiment describes a binomial experiment?
marshall27 [118]
Answer: the last option.
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In the first option, there is three possible outcomes (i.e. A, B, C)
In the second option, there is four poissible outcomes (i.e. ace, king, queen, jack)
The third option has six possible outcomes (i.e. six faces of a die)
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6 0
3 years ago
How would you solve this? Please give an explanation.
Neporo4naja [7]

The <em>first three</em> elements of the <em>recursive</em> series are 6, 10, 8. (Correct choice: B)

<h3>How to generate values from a recursive function</h3>

In this question we have a kind of <em>recursive</em> function known as Fibonacci's function, where a value of the series is generated from at least <em>immediately previous</em> elements. In this case, we need to find the <em>first</em> three elements from the <em>fifth</em> and <em>fourth</em> elements of the series:

a_{n-2} = a_{n-1} - a_{n} + 4

a₄ = a₅ - a₆ + 4

a₄ = - 2 - 0 + 4

a₄ = 2

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a₃ = 2 - (- 2) + 4

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a₂ = 10

a₁ = a₂ - a₃ + 4

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a₁ = 6

The <em>first three</em> elements of the <em>recursive</em> series are 6, 10, 8. (Correct choice: B)

To learn more on recursive series: brainly.com/question/8972906

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