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ki77a [65]
3 years ago
13

What was the cost of the family's clothing in 1991?

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

Answer:

B.

Step-by-step explanation:

Assuming the cost increased linearly is equivalent to assuming the cost increased at a constant rate. Because the cost of the clothing increased from $620 to $1,000 in 10 years, the constant rate is equal to

= ($1,000 - $620)/10

= $38 per year

Therefore, the cost of the family’s clothing in 1991 (6 years after 1985) is:

$620 + (6 years)($38 per year)

= $620 + $228

= $848

Olegator [25]3 years ago
5 0

Answer:

B. 848

Step-by-step explanation:

Hope it helps :>

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