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MatroZZZ [7]
2 years ago
9

If "z" is a standard normal variable, find the probability that "z" is less than 1.16. Sketch the graph and the required area.

Mathematics
1 answer:
mixer [17]2 years ago
7 0

Answer:

Step-by-step explanation:

It would be more obvious if it says z is a standard Normal variable and that the question is related to statistics.

From "Computing Probabilities Using the Cumulative Table" , the probability of z is less than 1.16, P(z<1.16) = 0.8770.

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Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds that the number of bacteria do
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Answer:

The population of bacteria can be expressed as a function of number of days.

Population = \[5*2^{n-1}\] where n is the number of days since the beginning.

Step-by-step explanation:

Number of bacteria on the first day=\[5 * 2^{0} = 5\]

Number of bacteria on the second day = \[5 * 2^{1} = 10\]

Number of bacteria on the third day = \[5*2^{2} = 20\]

Number of bacteria on the fourth day = \[5*2^{3} = 40\]

As we can see , the number of bacteria on any given day is a function of the number of days n.

This expression can be expressed generally as \[5*2^{n-1}\] where n is the number of days since the beginning.

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4 years ago
Convert 0.5 lbs to grams
Luda [366]

Answer:

226.796

Step-by-step explanation:

3 0
3 years ago
2e = 2 Solve the equation.
Kipish [7]

Answer:

e=1

Step-by-step explanation:

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3 years ago
Read 2 more answers
Suppose a horticulturist measures the aboveground height growth rate of four different ornamental shrub species grown in a green
torisob [31]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The decision is to <u>reject</u> the <u> null hypothesis</u> at a significant level of <u>significance </u> \alpha  = 0.05 There is <u>sufficient </u> evidence to conclude that <u>at least one of the population mean</u>  is <u>different from</u>  <u>at least of the population</u>  

Step-by-step explanation:

From the question we are told that the claim is

     The mean growth rates of all four species are equal.

The  null hypothesis is  

             H_o  :  \mu _1 =  \mu_2 = \mu_3  =  \mu_4

Th alternative hypothesis is    

             H_a: at \ least \ one \ of \  the \  means \ is \not\ equal

From question the p-value is p-value  =  0.015

  And since the p-value <  \alpha so the null hypothesis will be rejected

So  

   The decision is to <u>reject</u> the <u> null hypothesis</u> at a significant level of <u>significance </u> \alpha  = 0.05 There is <u>sufficient </u> evidence to conclude that <u>at least one of the population mean</u>  is <u>different from</u>  <u>at least of the population</u>  

7 0
3 years ago
The Jones family is considering which one of two businesses will mow their
Natalka [10]

Answer:

Lon's Lawns

Step-by-step explanation:

32X9=288

25X10+50=300

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