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barxatty [35]
2 years ago
14

Help meeeee;)........​

Mathematics
2 answers:
mylen [45]2 years ago
7 0

Step-by-step explanation:

ABC be the given isosceles right triangle such that <B = 90° , side AC is the hypotenuse; and, AB= BC

Then, (AB)^2 + (BC)^2 = (AC)^2…. Pythagoras theorem.

(AC)^2 = 98 sq. cm. ( given)

So, (AB)^2 + ((BC)^2 = 98

But, AB = BC = a ( say) …. ( given)

Therefore, a^2 + a^2 = 98

Or, 2a^2 = 98.

So, a^2 = 98 / 2 = 49

Hence, a = AB = BC = √49 = 7 cm.

The side AC ( the hypotenuse) = √98 = √(7 *7*2)

= 7 *√2 = 7* 1.414 = 9..898cm., say, 9.9 cm.

Hence, the three sides of the right isosceles triangle are 7 cm, 7cm and ~ 9.9 cm. Answer

<h2>please mark me as brainlist please </h2>

Katarina [22]2 years ago
6 0

Answer:

2) In an isoscles triangle, 2 sides are congruent.

Missing sides = x

In a right △,

Hypotenuse ² = Base² + Altitude ²

98 = x² + x²

98 = 2x²

98/2 = x²

49 = x²

√49 = x

7 = x

=》Length of the congruent sides = 7 cm

3) Using pythagorean property,

Hypotenuse ² = Base² + Altitude ²

10² = 6² + A²

10² - 6² = A²

100 - 36 = A²

64 = A²

8 cm = A

=》The upper end of the ladder touches the wall 8 cm above the ground.

4) AB = Hypotenuse = x

AC = Altitude = 7.2 cm

BC = Base = 2.1 cm

Hypotenuse ² = Base² + Altitude ²

x² = (2.1)² + (7.2)²

x² = 4.41 + 51.84

x² = 56.25

x = √56.25

x = 7.5 cm

=》 Length of AB = 7.5 cm

__________

Hope it helps ⚜

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X to the 3rd power= 64/343
leva [86]

Answer:

x = 4/7

Step-by-step explanation:

x^3 = 64/ 343 // - 64/ 343

x^3 - ( 64/ 343 ) = 0

x^3 - 64 / 343 = 0

1*x^3 = 64/ 343 // : 1

x^3 = 64/ 343

x^3 = 64/ 343 // ^ 1/3

x = 4/ 7

5 0
2 years ago
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
2 years ago
Please help thank you.
nikklg [1K]
I believe that through deductive reasoning angle O is 64 degrees. The reason is it's bigger than angle R so that rules out 32 and 16 degrees, but it's not obtuse, so that rules out 128 degrees, thereby leaving you with 64. Hope this helps :)
3 0
3 years ago
What is the square root of 248 + square root of 63​
enyata [817]

Answer:

1) √248 = ± 15.7480157

2)√63 = ± 7.93725393

 

Step-by-step explanation:

7 0
2 years ago
Solve/answer the question and help me understand this question please
faltersainse [42]

Answer:

  5.25 m

Step-by-step explanation:

A diagram can help you understand the question, and can give you a clue as to how to find the answer. A diagram is attached. The problem can be described as finding the sum of two vectors whose magnitude and direction are known.

__

<h3>understanding the direction</h3>

In navigation problems, direction angles are specified a couple of different ways. A <em>bearing</em> is usually an angle in the range [0°, 360°), <em>measured clockwise from north</em>. In land surveying and some other applications, a bearing may be specified as an angle east or west of a north-south line. In this problem we are given the bearing of the second leg of the walk as ...

  N 35° E . . . . . . . 35° east of north

Occasionally, a non-standard bearing will be given in terms of an angle north or south of an east-west line. The same bearing could be specified as E 55° N, for example.

<h3>the two vectors</h3>

A vector is a mathematical object that has both magnitude and direction. It is sometimes expressed as an ordered pair: (magnitude; direction angle). It can also be expressed using some other notations;

  • magnitude∠direction
  • magnitude <em>cis</em> direction

In the latter case, "cis" is an abbreviation for the sum cos(θ)+i·sin(θ), where θ is the direction angle.

Sometimes a semicolon is used in the polar coordinate ordered pair to distinguish the coordinates from (x, y) rectangular coordinates.

__

The first leg of the walk is 3 meters due north. The angle from north is 0°, and the magnitude of the distance is 3 meters. We can express this vector in any of the ways described above. One convenient way is 3∠0°.

The second leg of the walk is 2.5 meters on a bearing 35° clockwise from north. This leg can be described by the vector 2.5∠35°.

<h3>vector sum</h3>

The final position is the sum of these two changes in position:

  3∠0° +2.5∠35°

Some calculators can compute this sum directly. The result from one such calculator is shown in the second attachment:

  = 5.24760∠15.8582°

This tells you the magnitude of the distance from the original position is about 5.25 meters. (This value is also shown in the first attachment.)

__

You may have noticed that adding two vectors often results in a triangle. The magnitude of the vector sum can also be found using the Law of Cosines to solve the triangle. For the triangle shown in the first attachment, the Law of Cosines formula can be written as ...

  a² = b² +o² -2bo·cos(A) . . . . where A is the internal angle at A, 145°

Using the values we know, this becomes ...

  a² = 3² +2.5² -2(3)(2.5)cos(145°) ≈ 27.5373

  a = √27.5373 = 5.24760 . . . . meters

The distance from the original position is about 5.25 meters.

_____

<em>Additional comment</em>

The vector sum can also be calculated in terms of rectangular coordinates. Position A has rectangular coordinates (0, 3). The change in coordinates from A to B can be represented as 2.5(sin(35°), cos(35°)) ≈ (1.434, 2.048). Then the coordinates of B are ...

  (0, 3) +(1.434, 2.048) = (1.434, 5.048)

The distance can be found using the Pythagorean theorem:

  OB = √(1.434² +5.048²) ≈ 5.248

7 0
1 year ago
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