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3 years ago

Given the circle below with secants BCD and FED, find the length of BC.

Mathematics

1 answer:

Stells [14]3 years ago

8 0

It is 7.3 please give brainliest

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Six more than the product of a number and 5 is equal to 9.

padilas [110]

Answer:

5 = 9 + 6

Step-by-step explanation:

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2 years ago

A. B. 3(x+2) x+2 =18 =6 1) How can we get Equation BBB from Equation AAA? Choose 1 answer: Choose 1 answer: (Choice A) A

Alenkinab [10]

Answer:

D. Rewrite one side (or both) using the distributive property, Yes

Step-by-step explanation:

How can we get Equation BBB from Equation AAA? Based on the previous answer, are the equations equivalent? In other words, do they have the same solution?

5 0

3 years ago

Please anybody help me with this question

inn [45]

Answer:

y = 12

Step-by-step explanation:

Divide both by 1/4

x = 1 when y = 32/3

When x = 1 1/8 = 9/8

y = 32/3 x 9/8

y = 12

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3 years ago

What is 2x + 3y -4 =? <br><br> x = 2 , y =4

Vanyuwa [196]

Answer:

4X+12Y-4

Step-by-step explanation:

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3 years ago

Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type

Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

$\frac{y}{t} = e^{-kt + C} \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt} (A = e^{C})\\y = Ate^{-kt}$

when t = 1 hour, y = 15 grams. So,

$y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}$ (1)

when t = 3 hours, y = 30 grams. So,

$y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k}$ (2)

dividing (2) by (1), we have

$\frac{30}{15} = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}$

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

$A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36$

Substituting A and k into y, we have

$y = 18.36te^{-0.203t}$

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

$y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g$

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

3 0

3 years ago