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adell [148]
3 years ago
7

Eighth grade Algebra one

Mathematics
1 answer:
Travka [436]3 years ago
5 0

\Large{\red{\underline{\underline{\mathrm{ SOLUTION :- }}}}}

Here it is given that , a postal service charges a flat rate of 11.10 and a additional rate of 3 / kg .We need to write the equation in slope intercept form . And let ,

\sf\qquad\longrightarrow Total \ cost \ = \ y\\

\sf\qquad\longrightarrow Total\ weight\ = \ x

So the total cost would be the sum of flat rate plus the cost of the total weight . Therefore,

\sf\qquad\longrightarrow Cost_{weight}= \$3 \times x =\pink{\$3x}

Therefore the total cost would be,

\sf\qquad\longrightarrow Cost_{total}= Cost_{flat}+Cost_{weight}\\

\sf\qquad\longrightarrow y = \$11 + \$ 3x

Rearrange in slope intercept form , which is y = mx + c , as ;

\sf\qquad\longrightarrow \boxed{\pink{\sf y = \$3x + \$11}}

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masha68 [24]
P(not 5) =5/6 and P(5) = 1/6
If the first 5 is rolled on the 5th roll then the first four rolls were not 5
P(5 on fifth roll) = 5/6 x 5/6 x 5/6 x 5/6 x 1/6 = 5^4/6^5 = 625/7776 = 0.080375...
6 0
2 years ago
Which is the solution set to the given inequality |x+3|<12? x infinity(-15,9), x infinity {-15,9], x infinity (00,-15)U(9,00)
Viefleur [7K]

Answer:

Part 1) The solution set is (-15,∞) ∩ (-∞,9)=(-15,9)

Part 2) The ordered pair (1,3) is a solution of the system

Step-by-step explanation:

Part 1) we have

\left|x+3\right|

<u>First solution case Positive</u>

+(x+3)

x

x

The solution first case is the interval -------> (-∞,9)

<u>Second solution case Negative</u>

-(x+3)

-x-3

-x

-x ------> Multiply by -1 both sides

x>-15

The solution second case is the interval -------> (-15,∞)

The solution set is equal to

(-15,∞) ∩ (-∞,9)=(-15,9)  

Part 2) we have

y>-2 -------> inequality A

x+y\leq 4 -----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Verify each case

case a) (1,5)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

5>-2 ------> is true

<u>Inequality B</u>

1+5\leq 4

6\leq 4 -----> is not true

therefore

the ordered pair is not a solution

case b) (0,5)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

5>-2 ------> is true

<u>Inequality B</u>

0+5\leq 4

5\leq 4 -----> is not true

therefore

the ordered pair is not a solution

case c) (-2,-3)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

-3>-2 ------> is not true

therefore

the ordered pair is not a solution

case d) (1,3)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

3>-2 ------> is true

<u>Inequality B</u>

1+3\leq 4

4\leq 4 -----> is true

therefore

the ordered pair is  a solution

6 0
3 years ago
HELP RIGHT NOW!!! PLEASE VERY EASY!
BigorU [14]

Answer:

30 in^2

Step-by-step explanation:

get sides: 15, 18

multiply sides by 1/3: 5, 6

get area of square: 5*6= 30

5 0
3 years ago
Which is the graph of f(x) = 4^x
Zielflug [23.3K]
There is no graph, but if you didn’t mean to put a graph, the answer is you cannot put 4 to a power of anything, because that number is unknown, there is no possibly way to put 4 to the power of anything right now, you need to figure out the value of 4.
7 0
3 years ago
I need help!!! Brainliest for first (correct) answer!
VMariaS [17]

To do this without a calculator, I would change:  5.2 × 10^(-2) to ... 52×10^(-3)

--> then multiply the whole numbers 52 × 8 = 416

--> next add the exponents on the tens. -3 + -4 = -7

= 416×10^(-7)

* now they'll want you to move the decimal back to behind the first digit. (just standard convention)

= 4.16×10^(-5)

If you have a calculator you can just use the "EE" button for ×10^power typed in it looks like this :

5.2 EE -2 × 8 EE -4 =

then make sure your calculator is in scientific mode, otherwise you'll be counting decimal spaces

3 0
3 years ago
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