1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula to find the distance from point to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: .
THE ANSWER IS C HOPE THIS CAN HELP
Answer:
Step-by-step explanation:
The domain is the x value between - 5 and 7
The range is the y value between -2 and 6
You can find all sorts of definitions for the domain and range, but in this example it is really straight forward. If you put - 5 into the function, you get -2. If you put 7 into the function, you get 6. Now just draw a line between the two end points.
Answer:
x = 99.9
Step-by-step explanation:
628 = 2πx
---> x = 99.9
Make x the subject
2x = -3y + 1
5x = -2y -3
now times the answers to get the lcd
(2x = -3y + 1) x 5
10x = -15y + 5
(5x = -2y -3) 2
10x = -4y -6
now that they are equal to the same number:
-15y + 5 = -4y -6
-15y + 4y = -6 -5
-11y = -11
y = 1
now to find x we substitute y
2x = -3y + 1
2x = -3(1) + 1
2x = -3 + 1
2x = -2
x = -1