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hammer [34]
1 year ago
15

Solve each pair of simultaneous equations by elimination method.a) 2x+3y-1=0 5x+2y+3=0​

Mathematics
2 answers:
My name is Ann [436]1 year ago
7 0

Answer:

x = -1

y = 1

Step-by-step explanation:

<h2>PART I: Find the y-value</h2>

<u>Given expressions</u>

1) 2x + 3y - 1 = 0

2) 5x + 2y + 3 = 0

<u>Add 1 on both sides of the 1) equation:</u>

2x + 3y - 1 + 1 = 0 + 1

2x + 3y = 1

<u>Subtract 3 on both sides of the 2) equation:</u>

5x + 2y + 3 - 3 = 0 - 3

5x + 2y = -3

<u>Current System</u>

1) 2x + 3y = 1

2) 5x + 2y = -3

<u>Multiply 2.5 on both sides of the 1) equation</u>

(2.5) 2x + (2.5) 3y = (2.5) 1

5x + 7.5y = 2.5

<u>Current System</u>

1) 5x + 7.5y = 2.5

2) 5x + 2y = -3

<u>Subtract 2) equation from 1) equation</u>

(5x + 7.5y) - (5x + 2y) = 2.5 - (-3)

<u>Get rid of the parenthesis </u>

5x + 7.5y - 5x - 2y = 2.5 + 3

<u>Combine like terms</u>

5x - 5x + 7.5y - 2y = 5.5

0 + 5.5y = 5.5

5.5y = 5.5

<u>Divide 5.5 on both sides</u>

5.5y / 5.5 = 5.5 / 5.5

\boxed{y=1}

<h2>PART II: Find the x-value</h2>

<u>Substitute the y-value back to one of the equations to find the x-value</u>

2x + 3y - 1 = 0

2x + 3(1) - 1 = 0

<u>Combine like terms</u>

2x + 3 - 1 = 0

2x + 2 = 0

<u>Subtract 2 on both sides</u>

2x + 2 - 2 = 0 - 2

2x = -2

<u>Divide 2 on both sides</u>

2x / 2 = -2 / 2

\boxed{x=-1}

Hope this helps!! :)

Please let me know if you have any questions

Tanzania [10]1 year ago
5 0
Make x the subject
2x = -3y + 1
5x = -2y -3

now times the answers to get the lcd

(2x = -3y + 1) x 5
10x = -15y + 5

(5x = -2y -3) 2
10x = -4y -6

now that they are equal to the same number:
-15y + 5 = -4y -6
-15y + 4y = -6 -5
-11y = -11
y = 1

now to find x we substitute y
2x = -3y + 1
2x = -3(1) + 1
2x = -3 + 1
2x = -2
x = -1


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