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hammer [34]
1 year ago
15

Solve each pair of simultaneous equations by elimination method.a) 2x+3y-1=0 5x+2y+3=0​

Mathematics
2 answers:
My name is Ann [436]1 year ago
7 0

Answer:

x = -1

y = 1

Step-by-step explanation:

<h2>PART I: Find the y-value</h2>

<u>Given expressions</u>

1) 2x + 3y - 1 = 0

2) 5x + 2y + 3 = 0

<u>Add 1 on both sides of the 1) equation:</u>

2x + 3y - 1 + 1 = 0 + 1

2x + 3y = 1

<u>Subtract 3 on both sides of the 2) equation:</u>

5x + 2y + 3 - 3 = 0 - 3

5x + 2y = -3

<u>Current System</u>

1) 2x + 3y = 1

2) 5x + 2y = -3

<u>Multiply 2.5 on both sides of the 1) equation</u>

(2.5) 2x + (2.5) 3y = (2.5) 1

5x + 7.5y = 2.5

<u>Current System</u>

1) 5x + 7.5y = 2.5

2) 5x + 2y = -3

<u>Subtract 2) equation from 1) equation</u>

(5x + 7.5y) - (5x + 2y) = 2.5 - (-3)

<u>Get rid of the parenthesis </u>

5x + 7.5y - 5x - 2y = 2.5 + 3

<u>Combine like terms</u>

5x - 5x + 7.5y - 2y = 5.5

0 + 5.5y = 5.5

5.5y = 5.5

<u>Divide 5.5 on both sides</u>

5.5y / 5.5 = 5.5 / 5.5

\boxed{y=1}

<h2>PART II: Find the x-value</h2>

<u>Substitute the y-value back to one of the equations to find the x-value</u>

2x + 3y - 1 = 0

2x + 3(1) - 1 = 0

<u>Combine like terms</u>

2x + 3 - 1 = 0

2x + 2 = 0

<u>Subtract 2 on both sides</u>

2x + 2 - 2 = 0 - 2

2x = -2

<u>Divide 2 on both sides</u>

2x / 2 = -2 / 2

\boxed{x=-1}

Hope this helps!! :)

Please let me know if you have any questions

Tanzania [10]1 year ago
5 0
Make x the subject
2x = -3y + 1
5x = -2y -3

now times the answers to get the lcd

(2x = -3y + 1) x 5
10x = -15y + 5

(5x = -2y -3) 2
10x = -4y -6

now that they are equal to the same number:
-15y + 5 = -4y -6
-15y + 4y = -6 -5
-11y = -11
y = 1

now to find x we substitute y
2x = -3y + 1
2x = -3(1) + 1
2x = -3 + 1
2x = -2
x = -1


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Isabel will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $46 and costs an a
zaharov [31]

The missing part of the question is "For what amount of driving do the two plans cost the same"

The amount of driving that do the two plans cost the same is 450 miles

Step-by-step explanation:

Isabel will rent a car for the weekend. She can choose one of two plans

  • The first plan has an initial fee of $46 and costs an additional $0.13 per mile driven
  • The second plan has an initial fee of $55 and costs an additional $0.11 per mile driven

We need to find for what amount of driving do the two plans cost the same

Assume that she will drive for d miles

The first plan:

∵ The initial fee is $46

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∵ She will drive for d miles

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∴ The cost = 46 + 0.13 d ⇒ (1)

The second plan:

∵ The initial fee is $55

∵ The additional cost is 0.11 per mile

∵ She will drive for d miles

- The cost of her trip is the sum of $55 and the product of

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∴ The cost = 55 + 0.11 d ⇒ (2)

∵ The cost of the two plans is the same

- Equate (1) and (2) to find d

∴ 46 + 0.13 d = 55 + 0.11 d

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∴ 0.13 d = 0.11 d + 9

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∴ 0.02 d = 9

- Divide both sides by 0.02

∴ d = 450

The amount of driving that do the two plans cost the same is 450 miles

Learn more:

You can learn more about the word problems in brainly.com/question/3950386

#LearnwithBrainly

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Answer:

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