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2 years ago

The table represents a proportional relationship. Complete the table and write an equation that describes the relationship

Mathematics

2 answers:

notsponge [240]2 years ago

4 0

Can you post the table.

ivolga24 [154]2 years ago

3 0

Answer:

Which table?

There's non

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Question 4 please:<br> Witch numbers in the box are multiple of 3

umka21 [38]

Answer:

6 AND 12

Step-by-step explanation:

3 x 2 = 6

3 x 4 = 12

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3 years ago

Read 2 more answers

1-Find the missing number:

Yuki888 [10]

1) 23

2) 3

3) 6x+5 (I am not sure what they ask for)

4) -12+x

5) -56x + 16

6) -90+80x

7) -18x+45y-27

8) 6x+24y-42

9) 2/3w+x-1

10) -1.2wy +3y

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2 years ago

If y=6 when x=15 then which of thr following is the value of x when y=20

denis23 [38]

Answer:

if you meant x times y...

15 x 20 is 300.

if you meant x + y...

15 + 20 is 35.

if you meant anything else, please let me know

the way it was written confused me but I tried.

7 0

2 years ago

Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

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1 year ago

The sum of a rational number and irrational number is irrational.

tia_tia [17]

Answer:

A) Always True

6 0

3 years ago