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Maurinko [17]
2 years ago
5

What is the area of a rectangle with a length of 3 1/3 feet and a width of 1 2/3 feet?

Mathematics
1 answer:
BigorU [14]2 years ago
5 0

Answer:

area =l×b

= 3⅓ × 1⅔

= <u>1</u><u>0</u> × <u>5</u>

3. 3

<u>5</u><u>0</u>

9

= 5.56feet²

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He simultaneous equations<br>5x + y = 21<br>x - 3y = 9 <br><br>With working out​
Elza [17]

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

5x + y = 21 → (1)

x - 3y = 9 → (2)

Multiply (1) by 3 and add the result to (2) to eliminate y term

15x + 3y = 63 → (3)

Add (2) and (3) term by term

(x + 15x) + )- 3y + 3y) = (9 + 63)

16x = 72 ( divide both sides by 16 )

x = 4.5

Substitute x = 4.5 into (1) for corresponding value of y

22.5 + y = 21 ( subtract 22.5 from both sides )

y = - 1.5

Solution is (4.5, - 1.5 )

8 0
3 years ago
Problem is in the attached picture. Thanks in advance!
bogdanovich [222]

Answer:

Width= 120 ft

Length= 285 ft

Step-by-step explanation:

W= width and (3w-75)= length since it's 75 less than 3 times the width

w+w+(3w-75)+(3w-75)=810

8w-150=810

8w=960

w=120

So the width is 120 ft

Then substitute the 120 in for w in the length

L= 3(120)-75

L=360-75

L=285

So the length is 285 ft

You can check because 120+120+285+285=810, and because 120×3-75=285!

6 0
3 years ago
Will mark brainliest
faust18 [17]

x^3 is strictly increasing on [0, 5], so

\max\{x^3 \mid 0\le x\le5\} = 5^3 = 125

and

\min\{x^3 \mid 0 \le x\le5\} = 0^3 = 0

so the integral is bounded between

\displaystyle \boxed{0} \le \int_0^5x^3\,dx \le \boxed{125}

8 0
1 year ago
Please help with number 4,5,6,7,8 it will mean a lot
Xelga [282]
5) The slope is: 6

6) Answer: y=-1/2x+3

7) Answer: The slope is: -8, the y intercept is: 6

8) Answer: y=8x+30

Have a good day and a hug :D づ◡﹏◡)づ
6 0
2 years ago
How do I solve x-11/2&lt;-7
Mekhanik [1.2K]

Answer:

x < -3

Step-by-step explanation:

1. multiply both sides by 2

2. isolate the x by adding 11 to both sides

3. simplify

(i have included an attachment showing the work for clarification)

4 0
2 years ago
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