All categories

2 years ago

What is the area of a rectangle with a length of 3 1/3 feet and a width of 1 2/3 feet?

Mathematics

1 answer:

BigorU [14]2 years ago

5 0

Answer:

area =l×b

= 3⅓ × 1⅔

= 10 × 5

3. 3

50

= 5.56feet²

You might be interested in

Find an equation of the line described below. Write the equation is slope-intercept from ( solved for y), when possible. Through

Sladkaya [172]

Answer:

The equation of the line that is passing through the point (5,4) and is parallel to x-axis would be $y=4$

Step-by-step explanation:

Given that the line passes through the point (5,4).

As the line is parallel to the x-axis, the slope of the line would be zero.

And we have point (5,4) from which the line is passing.

So, $x_1=5\ ,\ y_1=4\ and\ m=0$

The equation of the line passing through point $(x_1,y_1)$ is

$y-y_1=m(x-x_1)\\y-4=0(x-5)\\y-4=0\\y=4$

So, the equation of the line that is passing through the point (5,4) and is parallel to x-axis would be $y=4$

4 0

3 years ago

Pls help me answer this question if correct I'll make brainylist!!!

Greeley [361]

Answer:

C. 11 3/4

Step-by-step explanation:

3 + 3 + 2 + 2 = 10

1/4 + 3/4 + 1/4 = 1 1/4

1/2 -> 2/4

2/4 + 1 1/4 = 1 3/4

10 + 1 3/4 = 11 3/4

6 0

3 years ago

Read 2 more answers

Divide to find equivalent fractions 18/10=

____ [38]

Answer:

9/5

Step-by-step explanation

18 divided by 10 equals 1.8 and 1.8 is 9/5 in fraction form.

4 0

3 years ago

Read 2 more answers

Find the distance between points M (6,16) and Z (-1,14) to the nearest tenth, please help step by step

insens350 [35]

The distance between 2 points P(a, b) and Q(c,d) is given by the formula:

$\displaystyle{d= \sqrt{(b-d)^2+(a-c)^2}$ ,

Apply the formula for the points M(6, 16) and Z(-1, 14):

$\displaystyle{d= \sqrt{(16-14)^2+(6-(-1))^2}= \sqrt{2^2+7^2}= \sqrt{4+49}= \sqrt{53}\approx 7.28$

which rounded to the nearest tenth is 7.3 (units)

Answer: 7.3 units

3 0

3 years ago

Can someone please help me!?

WITCHER [35]

A 5 is best predicted number

4 0

2 years ago