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anastassius [24]
2 years ago
8

NEED HELP ASAP PLEASE!!

Mathematics
1 answer:
Dimas [21]2 years ago
3 0
Hope this helps, btw i’m so bad at math but i found the answer from the app gauth.math

Answer:
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A figure is composed of a semicircle and a right triangle. Determine the area of the shaded region. Use 3.14 for π and round to
Aliun [14]

Answer:

A=9.5\ ft^2

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of triangle plus the area of semicircle

so

A=\frac{1}{2}bh+\frac{1}{2}\pi r^{2}

we have

b=4\ ft

Find the height of the right triangle applying the Pythagorean Theorem

5^2=h^2+4^2

h^2=9\\h=3\ ft

The radius of the semicircle is half the height of triangle

r=3/2=1.5\ ft

substitute in the formula

A=\frac{1}{2}(4)(3)+\frac{1}{2}(3.14)(1.5)^{2}

A=6+3.5=9.5\ ft^2

5 0
3 years ago
Read 2 more answers
Madaraka express arrived in Mombasa at 0545hrson Thursday after travelling for
Liono4ka [1.6K]

Answer:

Step-by-step explanation:

For this question, you count backwards from 0545hrs which is 5:45 am until 7hrs is reached.

5:45 am Thursday

↓

4:45 am Thursday

↓

3:45 am Thursday

↓

2:45 am Thursday

↓

1:45 am Thursday

↓

12:45 am Thursday

↓

11:45pm Wednesday

↓

10:45 pm Wednesday

Therefore, Madaraka express left Nairobi at 10:45 pm on Wednesday

4 0
3 years ago
3 ^(1 − 7 x = 7 ^x find the exact value
Shalnov [3]

Answer:

x

=

ln

(

3

)

7

ln

(

3

)

+

ln

(

7

)

Step-by-step explanation:

7 0
3 years ago
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A(n) _____ is a line drawn from one part of a circle's circumference to another without passing through the center.
Artemon [7]

Answer:

chord

Step-by-step explanation:

a chord is a line drawn from one part of a circle's circumference to another without passing through the centre.

If the line passed through the centre then it would be a diameter

7 0
2 years ago
H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
zubka84 [21]
H(x)=(x^2)+1\ \ \ \ and\ \ \ \  K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.
4 0
3 years ago
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