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2 years ago

Find the surface area of the rectangular prism include units and show work

Mathematics

1 answer:

jek_recluse [69]2 years ago

6 0

I think ur supposed to multiply all of the numbers

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HELP PLEASE IS FOR TODAY

babunello [35]

Answer:

It's A. segment A"B" is closer to segment C than segment A"B".

Step-by-step explanation:

5 0

3 years ago

Three hundred new ones cost $2100. what would be the cost of 120 new ones

SSSSS [86.1K]

Answer:

840

Step-by-step explanation:

120 is 40% of 300, and 840 is 40% of 2100 is 840.

5 0

3 years ago

Read 2 more answers

Which could be the name of a point? A. T B. 1 C. t D.m

azamat

Answer:

A. T

Step-by-step explanation:

6 0

3 years ago

Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The

ExtremeBDS [4]

Answer:

800 kph
600 kph

Step-by-step explanation:

Equation

Let s represent the speed of the faster plane. Then its travel time is ...

time = distance/speed = 3600/s

travel time for the slower plane is ...

time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

3600/(s -200) -3600/s = 1.5

Solution

Multiplying by (2/3)s(s -200), we get ...

2400(s) -2400(s -200) = s(s -200)

s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

(s -800)(s +600) = 0 . . . . . . . . . . . . . factor

The positive value of s that makes a factor zero is s = 800.

Conclusion

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

Check

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

6 0

3 years ago

"let v = r 2 with the usual addition and scalar multiplication defined by k(u1, u2) = (ku1, 0). determine which of the five axio

expeople1 [14]

Let $\mathbf u\in\mathbb R^2$ , where

$\mathbf u=(u_1,u_2)$

and let $k\in\mathbb R$ be any real constant.

Given this definition of scalar multiplication, we can see right away that there is no identity element $e$ such that

$e\mathbf u=\mathbf u$

because

$e\mathbf u=e(u_1,u_2)=(eu_1,0)\neq(u_1,u_2)=\mathbf u$

5 0

3 years ago