QUESTION 3
The sum of the interior angles of a kite is
.
.
.
.
.
But the two remaining opposite angles of the kite are congruent.

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QUESTION 4
RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.
Using the Pythagoras Theorem, we obtain;





QUESTION 5
The given figure is an isosceles trapezium.
The base angles of an isosceles trapezium are equal.
Therefore
QUESTION 6
The measure of angle Y and Z are supplementary angles.
The two angles form a pair of co-interior angles of the trapezium.
This implies that;



QUESTION 7
The sum of the interior angles of a kite is
.
.
.
.
.
But the two remaining opposite angles are congruent.

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.
.
.
QUESTION 8
The diagonals of the kite meet at right angles.
The length of BC can also be found using Pythagoras Theorem;




QUESTION 9.
The sum of the interior angles of a trapezium is
.
.
.
But the measure of angle M and K are congruent.
.
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.
Y = - pie/4
y = -0.785
I'm not sure if I'm right so u might wanna make sure
Answer:
He has 4 more to hang
Step-by-step explanation:
13 total; you must add the 5 he already hung in the morning plus, the 4 he hung in the afternoon; leaving you with 4 because 5 plus 4 is 9. 13 minus 9 is 4.
I just had the question and the correct answer is 36.