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sesenic [268]
3 years ago
10

Find the vector that translate A (-2, 7) to A' (6,4) *

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0

Answer:

Step-by-step explanation:

Nataly_w [17]3 years ago
6 0

A vector translation translates the figure on the coordinate from its current location to another

The vector that translates A(-2, 7) to A'(6, 4) is \dbinom{8}{-3}

The given preimage of the vector = A(-2, 7)

The given image of the vector = A'(6, 4)

Required: To find the vector that translates A(-2, 7) to A'(6, 4)

Solution:

The vector are given in component form, therefore, the vector, ΔA, that translates (moves from) vector A(-2, 7) to A'(6, 4) is the difference between the two vectors which is given as follows;

ΔA = A' - A = ((x' - x), (y' - y)

∴ ΔA = ((6 - (-2)), (4 - 7))

ΔA = (8, -3)

In vector form, vector that translates A to A' is \dbinom{8}{-3}

Learn more about vector translation here:

brainly.com/question/20840412

You might be interested in
Match each function with the corresponding function formula when h(x)=5-3x and g(x)=-3+5
Grace [21]

Answer:

k(x) = (3g + 5h)(x) ⇒ (1)

k(x) = (5h - 3g)(x) ⇒ (3)

k(x) = (h - g)(x) ⇒ (2)

k(x) = (g + h)(x) ⇒ (4)

k(x) = (5g + 3h)(x) ⇒ (5)

k(x) = (3h - 5g)(x) ⇒ (6)

Step-by-step explanation:

* To solve this problem we will substitute h(x) and g(x) in k(x) in the

  right column to find the corresponding function formula in the

  left column

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

- Lets start with the right column

# k(x) = (3g + 5h)(x)

∵ g(x) = -3^x + 5

∵ 3g(x) = 3[-3^x + 5] = [3 × -3^x + 3 × 5]

- Lets simplify 3 × -3^x

 take the negative out -(3 × 3^x), and use the rule a^n × a^m = a^(n+m)

∴ -3(3 × 3^x) = -(3^x+1)

∴ 3g(x) = -3^x+1 + 15

∵ h(x) = 5 - 3x

∵ 5h(x) = 5[5 - 3x] = [5 × 5 - 5 × 3x] = 25 - 15x

- Now substitute 3g(x) and 5h(x) in k(x)

∵ k(x) = (3g + 5h)(x)

∴ k(x) = -3^x+1 + 15 + 25 - 15x ⇒ simplify

∴ k(x) = 40 - 3^x+1 - 15x

∴ k(x) = 40 - 3^x+1 - 15x ⇒ k(x) = (3g + 5h)(x)

* k(x) = (3g + 5h)(x) ⇒ (1)

# k(x) = (5h - 3g)(x)

∵ 5h(x) = 25 - 15x

∵ 3g(x) = -3^x+1 + 15

∵ k(x) = (5h - 3g)(x)

∴ k(x) = 25 - 15x - (-3^x+1 + 15) = 25 -15x + 3^x+1 - 15 ⇒ simplify

∴ k(x) = 10 + 3^x+1 - 15x

∴ k(x) = 10 + 3^x+1 - 15x ⇒ k(x) = (5h - 3g)(x)

* k(x) = (5h - 3g)(x) ⇒ (3)

# k(x) = (h - g)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (h - g)(x)

∴ k(x) = 5 - 3x - (-3^x + 5) = 5 - 3x + 3^x - 5 ⇒ simplify

∴ k(x) = 3^x - 3x

∴ k(x)= 3^x - 3x ⇒ k(x) = (h - g)(x)

* k(x) = (h - g)(x) ⇒ (2)

# k(x) = (g + h)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (g + h)(x)

∴ k(x) = -3^x + 5 + 5 - 3x ⇒ simplify

∴ k(x) = 10 - 3^x - 3x

∴ k(x)= 10 - 3^x - 3x ⇒ k(x) = (g + h)(x)

* k(x) = (g + h)(x) ⇒ (4)

# k(x) = (5g + 3h)(x)

∵ g(x) = -3^x + 5

∵ 5g(x) = 5[-3^x + 5] = [5 × -3^x + 5 × 5] = 5(-3^x) + 25

∴ 5g(x) = -5(3^x) + 25

∵ h(x) = 5 - 3x

∵ 3h(x) = 3[5 - 3x] = [3 × 5 - 3 × 3x] = 15 - 9x

- Now substitute 5g(x) and 3h(x) in k(x)

∵ k(x) = (5g + 3h)(x)

∴ k(x) = -5(3^x) + 25 + 15 - 9x ⇒ simplify

∴ k(x) = 40 - 5(3^x) - 9x

∴ k(x) = 40 - 5(3^x) - 9x ⇒ k(x) = (5g + 3h)(x)

* k(x) = (5g + 3h)(x) ⇒ (5)

# k(x) = (3h - 5g)(x)

∵ 3h(x) = 15 - 9x

∵ 5g(x) = -5(3^x) + 25

∵ k(x) = (3h - 5g)(x)

∴ k(x) = 15 - 9x - [-5(3^x) + 25] = 15 - 9x + 5(3^x) - 25 ⇒ simplify

∴ k(x) = 5(3^x) - 9x - 10

∴ k(x) = 5(3^x) - 9x - 10 ⇒ k(x) = (3h - 5g)(x)

* k(x) = (3h - 5g)(x) ⇒ (6)

4 0
3 years ago
I NEED HELP PLEASE HELP ME
Aloiza [94]
Answer:
294.14cm^2

Explanation:

First find the area of the whole piece of paper:
32*14=448

Then find the area of the two semicircles, semicircle + semicircle = 1 circle:

Area of a circle= (radius squared)(pi):
(7^2)(3.14) = 153.86

Subtract the area of the two semicircles from the whole paper area:
448-153.86 = 294.14


I hope this isn’t too confusing :)


5 0
3 years ago
The gym teacher has $250 to spend on volleyball equipment. She buys 4 volleyball nets for $28 each. Volleyballs cost $7 each. Ho
pav-90 [236]

Answer:

The maximum number of volleyballs that she can buy is 19

Step-by-step explanation:

Let

x ----> the number of volleyballs

we know that

The cost of each volleyball net ($28) by the number of volleyball nets (4) plus the cost of each volleyball ($7) multiplied by the number of volleyballs (x) must be less than or equal to $250

so

The inequality that represent this situation is

28(4)+7x\leq 250

Solve for x

112+7x\leq 250

subtract 112 both sides

7x\leq 250-112

7x\leq 138

Divide by 7 both sides

x\leq 19.7

therefore

The maximum number of volleyballs that she can buy is 19

4 0
3 years ago
Answer my question please now :L
LUCKY_DIMON [66]

Answer:kdkejtjejejbf he neendhejrhwh

4 0
3 years ago
Read 2 more answers
What is the value of x in the equation 3(4x-1)-3x=5-(x-8)?
Setler [38]
12x-3-3x=5-(x-8)
9x-3=5-(x-8)
9x-3=5-x+ 8
9x-3=13-x
9x=16- x
10x=16
X= 8/5
4 0
3 years ago
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