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fgiga [73]
3 years ago
13

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=84°, and OP = 2. 9 feet. Find the length of PQ to the nearest tenth of a foot

Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0

OP= 27. 6

Step-by-step explanatexplanation:

In triangle OPQ: Ô+P+Q =180

therefore <P= 6°

OQ= OP sinsinà

OP= OQ/ sinà

OP= 2.9/ sin6°

OP= 27.7 ft

using pythagoras

OP^2 = PQ^2 + OQ^2

PQ= sqrt( 27.74^2 - 2.9^2)

PQ= 27.27.6

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