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rjkz [21]
2 years ago
9

In your US History class, you have scores of 78, 89, 87 and 96 on the first four tests. To get a B, the average of the five test

s must be greater than or equal to 80 and less than 90. Solve an inequality to find the range of the scores needed on the fifth test to get a B
Mathematics
2 answers:
Digiron [165]2 years ago
8 0
Let x be the score of the fifth test. 

a) let's find the value of x so that to get 80. To that end use the average notion:
(78+89+87+96+x)/5 = 80
(350 + x)/5 = 80. Cross multiplication
350+x = 400  and x = 50

b) let's find the value of x so that to get 90. To that end use the average notion:
(78+89+87+96+x)/5 = 90
(350 + x)/5 = 0. Cross multiplication
350+x = 450  and x = 100

Then the value of x should be:

50 < x < 100


Vaselesa [24]2 years ago
3 0
Well, since it is asking for an average, we have to add
78+89+87+96=
350... then we divide by 4
which would be 87.5 which IS greater than 80 :)
and less than 90 :)

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What is the area of the composite figure? (use 3.14 for pi). Explain how you arrived at your answer. Please round to the nearest
maksim [4K]

The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

                 Given diagram is combination of Rectangle and Semi circle.

Step:1

         Res the attachment,

                      Area of given diagram = Area of A + Area of B..............(1)

Step:2

         For A,

         The A section in the given diagram is semi circle,

                     Diameter of semi circle = Total distance - ( 2+3)

                                          ( ∵ 2, 3 are top distance in the given diagram)

                                                             = 10 - 5

                                        Diameter, d = 5 cm

                                             Radius, r = \frac{d}{2}

                                                          r = \frac{5}{2}

                                                         r = 2.5 cm

                                          Area, A_{A}  = \frac {\pi r^{2} }{2}........................(2)

                                                    A_{A}  = \frac {\pi (2.5)^{2} }{2}  

                                                           = \frac {\pi ( 6.25) }{2}

                                                           = \frac{19.63}{2}

                                                     A_{A} = 9.8174 cm^{2}

Step:3

               For B,

               Area of rectangle is,

                                                      A_{B} =lb.....................(3)

              Where, l - Length = 10 cm

                          b - Width = 2 cm

              Equation (3) become,

                                                            = (10)(2)

                                                            = 20

                                    Area of B, A_{B} = 20 cm^{2}

Step:4

               From the equation (1),

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                                                            Area = 29.817 square centimeters

Result:

            The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

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