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2 years ago

14

The frequency of a wavelength ?

1 answer:

serious [3.7K]2 years ago

6 0

Answer:

$f=0.1$

Explanation:

Use the equation:

$f=\frac{1}{T}$ (where T is the period)

$f=\frac{1}{9}$ (9 comes from the period of a full wavelength)

$f=0.1$

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How is the scientific use of the term digital different from the common use

masha68 [24]

The scientific use of "digital" is usually used to describe signals and other entities that have an "either/or" value. An example is the binary system where 1 represents an "on" and 0 represents an "off"
The common use of digital implies anything that is electron, be it analogue or digital.

5 0

3 years ago

Two isolated copper plates, each of area 0.40 m2, carry opposite charges of magnitude 7.08 × 10-10 C. They are placed opposite e

polet [3.4K]

Answer:

The potential difference between the plates is 8 V.

Explanation:

Given that,

Area of plates = 0.40 m²

Charge $q=7.08\times10^{-10}\ C$

Distance = 4.0 cm

We need to calculate the electric field

Using for formula of electric field

$E=\dfrac{2q}{2\epsilon_{0}A}$

Where, q = charge

A = area

Put the value into the formula

$E=\dfrac{7.08\times10^{-10}}{8.85\times10^{-12}\times0.40}$

$E=200\ V/m$

We need to calculate the potential difference between the plates

Using formula of potential difference

$V=E\times d$

Where, E = electric field

d = distance

Put the value into the formula

$V=200\times0.04$

$V=8\ V$

Hence, The potential difference between the plates is 8 V.

3 0

4 years ago

If 128 g of material is in the shape of a brick 2 cm wide, 4 cm high, and 8 cm long, what is the density of the material?

Nastasia [14]

Answer:

2000 kg/m³

Explanation:

Density = (mass[kg])/(volume[m³])

Density of the brick = (.128kg)/(.02•.04•.08) = 2000 kg/m³

3 0

3 years ago

The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s.

Aleks [24]

By definition, centripetal acceleration is given by:

$a = \frac{v ^ 2}{r}$

Where,

v: tangential disk speed

r: disk radius

Substituting values in the given equation we have:

$a =\frac{3.3^2}{0.13}\\a = 83.76923077$

Rounding the result we have:

$a = 83.8 \frac{m}{s^2}$

Answer:

The centripetal acceleration of the disc edge in m/s^2 is:

$a = 83.8 \frac{m}{s^2}$

3 0

4 years ago

Read 2 more answers

You are in charge of a cannon that exerts a force 11500 N on a cannon ball while the ball is in the barrel of the cannon. The le

IRISSAK [1]

Answer:

m = 7.48 kg

Explanation:

force (f) = 11,500 N

length of barrel (s) = 1.7 m

angle above the ground = 49.3 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

initial velocity (u) = 0 m/s

final velocity (v) = 72.3 m/s

mass (m) = ?

force = mass (m) x acceleration (a)

acceleration (a) = force / mass (m)

acceleration (a) = 11500 / m

applying the equation of motion $v^{2} = u^{2} + 2as$ , we can get the mass

$72.3^{2} = 0^{2} + (2 x \frac{11500}{m} x 1.7 )$

5227.3 = 0 + $\frac{39100}{m}$

m = $\frac{39100}{5227.3}$

m = 7.48 kg

5 0

3 years ago