B. 8.89 (hope this helped.)
You can solve by just doing 3.5in * 2.54
Hi!
The answers would be <u>chunking</u> & <u>short-term</u>
1. <u>Chunking </u>involves organizing and breaking down information into easier groups to expand capacity.
<h3>Explanation:</h3>
Chunking is a mental process that is observed to increase short-term memory by taking the information and categorizing it into small groups. For instance, a longer number taken as a single unit is harder to recall then when it is divided into smaller units. 235469350 is harder to instantly recall as compared to when it is chunked into 3 groups: 235 469 350.
This allows more information to be stored in, thereby increasing the capacity of the mind to store information.
2. Rehearsal is the verbal repetition of information. These techniques are especially important for the improvement of <u>short-term</u> memory.
<h3>Explanation: </h3>
Short-term memory is lost after a couple of seconds or minutes, for instance even if you chunk the information, you might not recall it after 30 seconds. Rehearsing or repetition of information, either loudly or mentally, extends the time a particular information is retained.
So you depending on the number of times you repeat the number 235 469 350, the more your short term memory improves .
Hope this helps!
I think the answer is "<span>The ball that went out of the park shows more work because the distance was greater."</span>
Answer:
11.18 minutes
Explanation:
We shall apply Newton's law of cooling
Rate of cooling ∝ Temperature difference
(T₂ - T₁ ) / t = k ( T₁ + T₂ / 2 - T )
A body cools from temperature of T₂ TO T₁ in time t , K being a constant.
(T₁ + T₂) /2 is the average temperature and T is temperature of surrounding.
Using the data given in the problem ,
For cooling from 425 degree to 300 degree
For cooling from 425 to 135 in time t we have
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= 209k
From these two equations we get the value of t as
t = 16.18 s
So time required to cool from 300 to 135 degree isas follows
16.18 - 5 = 11.18 s
Answer:
The acceleration of the proton is 1.403 x 10⁹ m/s²
Explanation:
Given;
speed of proton, v = 7.7 m/s
magnitude of magnetic field, B = 1.9 T
Magnetic force of moving proton is given by;
F = qvBsinθ
Centripetal force on the moving proton is given by;
where;
q is charge of the proton = 1.602 x 10⁻¹⁹ C
m is mass of proton = 1.67 x 10⁻²⁷ kg
Therefore, the acceleration of the proton is 1.403 x 10⁹ m/s²