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2 years ago

Simplify the expression. 28 + 4 2 A. 9 B. 11 C. 16 D. 22

Mathematics

2 answers:

padilas [110]2 years ago

8 0

Answer:

C) 16

Step-by-step explanation:

$\dfrac{28+4}{2}=\dfrac{32}{2}=16$

Andrew [12]2 years ago

6 0

$\\ \rm\hookrightarrow \dfrac{28+4}{2}$

Break

$\\ \rm\hookrightarrow \dfrac{28}{2}+\dfrac{4}{2}$

Solve

$\\ \rm\hookrightarrow 14+2$

$\\ \rm\hookrightarrow 16$

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Thomas has $6.35 in dimes and quarters. The number of dimes is three more than three times the number of quarters. How many quar

Lorico [155]

The total amount of x values of dimes and q values of quarters is equal to 6.35. From the given, the number of dimes may also be expressed as, 3q + 3. The equation that best represent the given is,
(3q + 3)(0.1) + q(0.1) = 6.35

6 0

3 years ago

Read 2 more answers

In how many ways can five basketball players be placed in three positions?

Georgia [21]

Answer:

10 ways

Step-by-step explanation:

The number of ways in which five basketball players could be placed in three positions is:

5 $C_{3}$ = $\frac{5!}{(5-3)!3!}$

= $\frac{5!}{3!2!}$

= $\frac{5*4*3*2!}{3*2*2!}$

= 5 × 2

= 10

The basketball players can be arranged in 10 ways.

4 0

3 years ago

Factor the expression given below. Write each factor as a polynomial in

bezimeni [28]

Answer:

3(343=72y)

Step-by-step explanation:

343x3=1029

1029+216y

both divisible by 3

3(343=72y)

6 0

3 years ago

Find the equation in standard form of the line with slope

Serhud [2]

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 5}}\quad ,&{{ 7}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{7}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-7=\cfrac{7}{2}(x-5)\implies y-7=\cfrac{7}{2}x-\cfrac{35}{2}
\\\\\\
y=\cfrac{7}{2}x-\cfrac{35}{2}+7\implies \stackrel{standard~form}{-\cfrac{7}{2}x+y=-\cfrac{21}{2}}$

3 0

3 years ago

Subtract 3/y-2 - 1/y+3

Helen [10]

To subtract fractions, we need a common denominator.

$\frac{3}{y-2}$ - $\frac{1}{y+3}$

the common denominator will be (y-2)(y+3)

$\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}$
$\frac{3y + 9 - y + 2}{(y-2)(y+3)}$
$\frac{2y + 11}{(y-2)(y+3)}$

The answer above will be the simplified form.

3 0

3 years ago