I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
For one moth it would be....

$57.00 In total but im not sure if this is correct so if you could make sure please.
In a set of data, if the data is perfectly symmetrical then the mean is equal to the median. In this case, the median would be 50.
For example, consider the data set: {25, 50, 75}
The mean is going to be 50 because
= 50
The median is also 50 because that is the middle number when ordered numerically.
Hope this helped! Let me know if you have any more questions.
Answer:
11 17/21
Step-by-step explanation:
-6 7/8 /(-3 3/4)
55/8X4/15
11/6
1 5/6