Answer:
Explanation:
• The initial dose of the Insulin = 10 Units
The insulin breaks down by about 5% each minute, therefore:
• The decay rate, r= 5%
We want to determine the time it will take for the remaining dosage to be half (5 units) of the original dose.
We use the exponential decay function:
Substituting the given values, we have:
To solve for t, we change to logarithm form.
Answer:
4600
Step-by-step explanation:
it is simply the sum of home credit which is
=3000 + 1600
=4600
Answer:
41.7m²
Step-by-step explanation:
As we can see, the area of this shape is simply the sum of 3 rectangles
Rectangle A has an area of 6 times 4 or 24m²
Rectangle B has an area of (3.8-2) times 3.5 or 1.8 times 3.5 or 6.3m²
Rectangle C has an area of 3 times 3.8 or 11.4m²
Adding that up gives 41.7m²
Answer:
a) W₁ = 78400 [J]
b)Wt = 82320 [J]
Step-by-step explanation:
a) W = ∫ f*dl general expression for work
If we have a chain with density of 10 Kg/m, distributed weight would be
9.8 m/s² * 10 kg = mg
Total length of th chain is 40 m, and the function of y at any time is
f(y) = (40 - y ) mg where ( 40 - y ) is te length of chain to be winded
At the beggining we have to wind 40 meters y = 0 at the end of the proccess y = 40 and there is nothing to wind then:
f(y) = mg* (40 - y )
W₁ = ∫f(y) * dy ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy
W₁ = mg [ 40*y |₀⁴⁰ - 1/2 * y² |₀⁴⁰ ⇒ W₁ = mg* [ 40*40 - 1/2 (40)² ]
W₁ = mg * [1/2] W₁ = 10*9,8* ( 800 )
W₁ = 78400 [J]
b) Now we can calculate work to do if we have a 25 block and the chain is weightless
W₂ = ∫ mg* dy ⇒ W₂ = ∫₀⁴⁰ mg*dy ⇒ W₂ = mg y |₀⁴⁰
W₂ = mg* 40 = 10*9.8* 40
W₂ = 3920 [J]
Total work
Wt = W₁ + W₂ ⇒ Wt = 78400 + 3920
Wt = 82320 [J]
Just substitute the value x into the equation y=2x
y = 2x
y = 2(-1)
y = -2
use the same method for the rest
