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2 years ago

What is the LCM of 10 and 15?

Mathematics

2 answers:

dexar [7]2 years ago

8 0

Step-by-step explanation:

lana [24]2 years ago

8 0

Answer:

Step-by-step explanation:

First, you must find the prime factorization of the two numbers:

10 = 2 x 5

15 = 3 x 5

Now you just multiply their factors, but since 5 is a factor of both numbers you only need to multiply by 5 once.

2 x 3 x 5 = 30

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Answer:

c. 1,417

Step-by-step explanation:

200,000 (8.5%) = 17,000

17,000 / 12 = 1,416.67 or 1,417

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2 years ago

there are 120 students in a school marching band. they march in an array with the same number of students in each row. what are

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Answer:

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Step-by-step explanation:

20 X 6 = 120 I'm not smart but this is pretty easy

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2 years ago

What is the answer of this equation

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Put it in an improper fraction by multiply the coefficient with the denominator and add the numerator.
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3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%3F%7D%7B5%7D%20%2A%20%5Cfrac%7B10%7D%7B8%7D%20%3D1.5%5C%5C" id="TexFormula1" title=

Serggg [28]

Answer:

$\boxed{\sf \huge \boxed{ \sf ?} = 6}$

Step-by-step explanation:

$\sf Solve \: for \: \boxed{ \sf ?} : \\ \sf \implies \frac{\boxed{ \sf ?}}{5} \times \frac{10}{8} = 1.5 \\ \\ \sf \implies \frac{\boxed{ \sf ?} \times 10}{5 \times 8} = 1.5 \\ \\ \sf \frac{10}{5} = \frac{ \cancel{5} \times 2}{ \cancel{5}} = 2 : \\ \sf \implies \frac{ \boxed{ \sf 2} \times \boxed{ \sf ?} }{8} = 1.5 \\ \\ \sf \frac{2}{8} = \frac{ \cancel{2}}{ \cancel{2} \times 4} = \frac{1}{4} : \\ \sf \implies \frac{\boxed{ \sf ?}}{ \boxed{ \sf 4}} = 1.5 \\ \\ \sf Multiply \: both \: sides \: of \: \frac{\boxed{ \sf ?}}{4} = 1.5 \: by \: 4 : \\ \sf \implies \frac{4 \times \boxed{ \sf ?}}{4} = 4 \times 1.5 \\ \\ \sf \frac{4 \times \boxed{ \sf ?}}{4} = \frac{ \cancel{4}}{ \cancel{4}} \times \boxed{ \sf ?} = \boxed{ \sf ?} : \\ \sf \implies \boxed{\boxed{ \sf ?}} = 4 \times 1.5 \\ \\ \sf 4 \times 1.5 = 6 : \\ \sf \implies \boxed{ \sf ?} = 6$

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2 years ago

What is the range of f(x) = 3x + 9?

11Alexandr11 [23.1K]

There is no restriction upon the domain, the x values, and is all real numbers or (-oo,+oo)

From such it is clear that the domain also contains all real numbers.

The range of f(x) is (-oo,+oo)

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2 years ago