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Step2247 [10]
3 years ago
6

The table below gives percent of flights that were delayed and on time during good and bad weather. Good weather Bad Weather Del

ayed 7.5% 17.5% On Time 42.5% 32.5% Given these percentages, during bad weather, is it more likely that your flight will be delayed or on time? How much more likely? It is 30% more likely to be delayed. It is 15% more likely to be delayed. It is 30% more likely to be on time. It is 15% more likely to be on time.
Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0
The answer would be: It is 15% more likely to be delayed.
<span>
The table should look like this:
              Good weather Bad Weather
Delayed 7.5%                17.5%
On Time 42.5%             32.5% 

The question is asking whether the probability when "bad weather" and "on time" more likely than "On time". So, you need to find the difference between them. The calculation would be:32.5%- 17.5%= 15%</span>
Maurinko [17]3 years ago
3 0

Answer:

The correct answer is 30% likely to be on time

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Eduardwww [97]
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3 years ago
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Find a tangent vector of unit length at the point with the given value of the parameter t. r(t) = 2 sin(t)i + 7 cos(t)j t = π/6
alina1380 [7]

The tangent vector to r(<em>t</em>) at any <em>t</em> in the domain is

\mathbf T(t)=\dfrac{\mathrm d\mathbf r(t)}{\mathrm dt}=2\cos t\,\mathbf i-7\sin t\,\mathbf j

At <em>t</em> = π/6, the tanget vector is

\mathbf T\left(\dfrac\pi6\right)=\sqrt3\,\mathbf i-\dfrac72\,\mathbf j

To get the unit tangent, normalize this vector by dividing it by its magnitude:

\left\|\mathbf T\left(\dfrac\pi6\right)\right\|=\sqrt{(\sqrt3)^2+\left(-\dfrac72\right)^2}=\dfrac{\sqrt{61}}2

So the unit tangent at the given point is

\dfrac{\mathbf T\left(\frac\pi6\right)}{\left\|\mathbf T\left(\frac\pi6\right)\right\|}=2\sqrt{\dfrac3{61}}\,\mathbf i-\dfrac7{\sqrt{61}}\,\mathbf j

4 0
3 years ago
What is the solution to the inequality below?
Marina CMI [18]

Answer:

x> 49    answer : D

Step-by-step explanation:

hello :

√x > 7

(√x)² >( 7)²

x> 49    answer : D

5 0
3 years ago
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leonid [27]

Answer:

Domain: 5, 6, 7, 8

Range: 0, -2, 10, -3

The relation is a function because each x-value has its own y-value.

Step-by-step explanation:

Domain: Set of all first elements in relation

Range: Set of all second elements in relation

How to determine if the relations is a function:

1. Identify the input values.

2. Identify the output values.

3. If each input value leads to only one output value, classify the relationship as a function.

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no

Step-by-step explanation:

5(4x+3) = 20x+15 which isnt 20x+3

8 0
3 years ago
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