Multiply -2 by 3z and -4y
-6z + 8y -z
subtract z from -6z
-7z + 8y should be your answer
Answer:
Mathematical domain is all numbers, as all numbers can be multiplied by 4. However, this is not reasonable as negative lengths don't exist, so the reasonable domain would be all positive numbers.
The mean, variance, and standard deviation are 1, 8,33 and 2.89
<h3>How to find the mean, variance, and standard deviation?</h3>
The distribution is given as:
[a, b] = [-4, 6]
The mean is calculated as;
Mean = (a + b)/2
So, we have
Mean = (-4 + 6)/2
Evaluate
Mean = 1
The variance is calculated as;
Var = (b - a)^2/12
So, we have
Var = (6 + 4)^2/12
Evaluate
Var = 8.33
The standard deviation is calculated as;
SD= sqrt(Var)
So, we have
SD = sqrt(8.33)
Evaluate
SD = 2.89
Hence, the mean, variance, and standard deviation are 1, 8,33 and 2.89
Read more about uniform distribution at:
brainly.com/question/16238191
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Answer:
- The graphed is attached.
- It's an enlargement.
Step-by-step explanation:
A Dilation is defined as a transformation in which the image and the pre-image have the same shape, but their sizes are different.
When the scale factor is greater than 1, the image obtained after the dilation is greater than the pre-image and it is an "Enlargement".
When the scale factor is is between 0 and 1, the image obtained after the dilation is smaller than the pre-image and it is an "Reduction".
In this case we know that the scale factor is 4.
Since:

So it is an Enlargement.
Now we need to multiply the coordinates of the vertices of VWXY by 4, in order to find the coordinates of the vertices of V'W'X'Y'. These are:

Now we must draw the pre-image and the pre-image and label them, as you see in the picture attached.
Lets imagine that we have:
Y = Sec(θ).Cos(θ)
As Sec(θ) = 1/Cos(θ)
Then we stay:
Y = 1/Cos(θ). Cos(θ)
Cos(θ) from up, will cut with Cos(θ) from down.
Then,
Y = 1