Answer:
34% see explanation below
Step-by-step explanation:
The total number who likes pizza is 73 and the total number of people surveyed is 215
So it'll just be 73/215 × 100 (for the percentage)
Answer: 30
Step-by-step explanation: Free math problem solver answers your algebra homework questions with step-by-step explanations.
You visited this page on 12/2/21.
The factors of rty are
1, r, t, y,
rt, ry, ty, rty
2 because the equation can be reduced to: 8.0 x 10^4.
Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, the parameters are:

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
More can be learned about the z-distribution at brainly.com/question/25890103