Find the total number of cards in a deck. Count all the # 3’s total cards/#3 cards
Count all the clubs total card/ clubs
Not sure if you are counting 3’s & clubs together. If you are, total cards/ both
So all you have to do is count & then divide to get the probability.
Answer:
No, it is not a right triangle.
Step-by-step explanation:
The simplest way to determine is testing out the numbers with Pythagorian theorem.
If it complies with the theorem, it is a right triangle.
let's assume c = 28, b = 21, and a = 20
the longest side is the hypotenuse so side c (28 in) will be the hypotenuse.
According to the Pythagorian theorem, the square of the length of hypotenuse must equal to the sum of squares of other two sides.
check:
c^2 = 28^2 = 784
a^2 + b^2 = 21^2 + 20^2 = 841
because c^2 is not equal to a^2 + b^2, the triangle is not a right triangle.
W=4L/9
A=LW, using W found above gives us
A=L(4L/9)
A=4L^2/9 and we were told that A=576 so
4L^2/9=576 multiply both sides by 9
4L^2=5184 divide both sides by 4
L^2=1296 take the square root of both sides
L=36, and we know that W=4L/9 so
W=4(36/9)=16
So the dimensions are: width=16in and length=36in
In this situation you would have to use ratios to figure it out.
AD over EH or 24/16 that would be equal to 1.5
This would show that BC over GF is also equal to 1.5.
6/4 is equal to 1.5.
Side length BC is 6
A calculate the bounce height for each and work out the total
b do it again and use a stopwatch and calulate. Hope this helped
