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nexus9112 [7]
1 year ago
10

A telephone company charges a $0.25

Mathematics
1 answer:
Marta_Voda [28]1 year ago
5 0

The value of a dependent variable is dependent on the value of an independent variable. The correct option is C.

<h3>What are independent and dependent variables?</h3>

Even though everything can be almost always related to its reason, when we talk about two related things, there might happen that one of those things is dependent on other.

  • If a variable is taking its values independently of any visible direct cause, then that variable is called independent variable.
  • The variables who take their values based on some other variables' values are called dependent variables.

The complete question is:

A telephone company charges a $0.25 connection fee, then $0.10 per minute for long distance calls. Which statement is true regarding this situation?

A. The rate of change is $0.25 and minutes are the independent variable.

B. The rate of change is $0.25 and minutes are the dependent variable.

C. The rate of change is $0.10 per minute and minutes are the independent variable

D. The rate of change is $0.10 per minute and minute are the dependent variable.

The cost of making a call is the sum of the cost of connection fee which is one time fee and cost $0.25, and the cost charged for a minute which depends on the number of minute for which the call is been established. Therefore, the total cost can be written for a x minute call is,

Total Cost = $0.25 + $0.10(x)

Since the total cost is dependent on x, therefore, x which is the minute is the independent variable. The rate of change is $0.10 per minute and minutes are the independent variable.

Hence, the correct option is C.

Learn more about Dependent and Independent Variable:

brainly.com/question/27795876

#SPJ1

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Find the function y = f(t) passing through the point (0, 18) with the given first derivative.
monitta

Answer:

\displaystyle y = \frac{t^2}{16} + 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Functions
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  • Coordinates (x, y)

<u>Calculus</u>

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Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]:                                                                   \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:                                                             \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (0, 18)

\displaystyle \frac{dy}{dt} = \frac{1}{8} t

<u>Step 2: Find General Solution</u>

<em>Use integration</em>

  1. [Derivative] Rewrite:                                                                                         \displaystyle dy = \frac{1}{8} t\ dt
  2. [Equality Property] Integrate both sides:                                                        \displaystyle \int dy = \int {\frac{1}{8} t} \, dt
  3. [Left Integral] Integrate [Integration Rule - Reverse Power Rule]:                 \displaystyle y = \int {\frac{1}{8} t} \, dt
  4. [Right Integral] Rewrite [Integration Property - Multiplied Constant]:           \displaystyle y = \frac{1}{8}\int {t} \, dt
  5. [Right Integral] Integrate [Integration Rule - Reverse Power Rule]:              \displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C
  6. Multiply:                                                                                                             \displaystyle y = \frac{t^2}{16} + C

<u>Step 3: Find Particular Solution</u>

  1. Substitute in point [Function]:                                                                         \displaystyle 18 = \frac{0^2}{16} + C
  2. Simplify:                                                                                                             \displaystyle 18 = 0 + C
  3. Add:                                                                                                                   \displaystyle 18 = C
  4. Rewrite:                                                                                                             \displaystyle C = 18
  5. Substitute in <em>C</em> [Function]:                                                                                \displaystyle y = \frac{t^2}{16} + 18

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

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The picture shows a circular clock face.
marysya [2.9K]

Answer:

[C] 25π square inches

Step-by-step explanation:

<u><em>Given that:</em></u>

<em>the long hand of the clock is about 5 inches long.</em>

<u><em>To Find:</em></u>

<em>What is the approximate area of the clock face?</em>

<u><em>Solve:</em></u>

<em>Formula - </em><em>A =πr²</em>

<em>Note that;</em>

<em>π = 3.14 (about)</em>

<em>Radius - 5 inches</em>

<em>A =πr²</em>

<em>A = 3.14(5)²</em>

<em>A = 3.14(25)</em>

<em>A = 78.5</em>

<em>Now let see the answer choices:</em>

<em>A.  5π square inches                     ≈   5(3.14) = 15.7</em>

<em>B. 10 π square inches                    ≈  10(3.14) = 31.4</em>

<em>C. 25 π square inches                    ≈  25(3.14) = 78.5</em>

<em>D. 100 π square inches                    ≈ 100(3.14) = 314</em>

<em />

<em>Hence, the answer is [C] 25 π square inches </em>

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Answer:

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