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2 years ago

One more time help????

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

8 0

A= 8ft
B= 4ft
C=6ft
D=10ft

SA=144ft

2 triangles: 6(8)/2= 24
rectangle 1: 4(6)= 24
rectangle 2: 4(8)= 32
rectangle 3: 4(10)= 40
SA= 24+24+24+32+40
SA=144

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2. Which is the following equation rewritten in slope-intercept form: -8x = 2 - 2y

Anna007 [38]

Answer:

B, y = 4x + 1

Step-by-step explanation:

to get it into y- intercept form we need to write it in the form y = mx + b

-8x = 2 - 2y, move 2y to the other side and -8x to the other side they both become positive.

2y = 8x + 2, dividing each by 2

yields y = 4x + 1

Hope this helps

8 0

3 years ago

Differentiate with respect to x and simplify your answer. Show all the appropriate steps? 1.e^-2xlog(ln x)^3 2.e^-2x(log(ln x))^

serious [3.7K]

(1) I assume "log" on its own refers to the base-10 logarithm.

$\left(e^{-2x}\log(\ln x)^3\right)'=\left(e^{-2x}\right)'\log(\ln x)^3+e^{-2x}\left(\log(\ln x)^3\right)'$

$=-2e^{-2x}\log(\ln x)^3+\dfrac{e^{-2x}}{\ln10(\ln x)^3}\left((\ln x)^3\right)'$

$=-2e^{-2x}\log(\ln x)^3+\dfrac{3e^{-2x}(\ln x)^2}{\ln10(\ln x)^3}\left(\ln x\right)'$

$=-2e^{-2x}\log(\ln x)^3+\dfrac{3e^{-2x}(\ln x)^2}{\ln10\,x(\ln x)^3}$

$=-2e^{-2x}\log(\ln x)^3+\dfrac{3e^{-2x}}{\ln10\,x\ln x}$

Note that writing $\log(\ln x)^3=3\log(\ln x)$ is one way to avoid using the power rule.

(2)

$\left(e^{-2x}(\log(\ln x))^3\right)'=(e^{-2x})'(\log(\ln x))^3+e^{-2x}\left(\log(\ln x))^3\right)'$

$=-2e^{-2x}(\log(\ln x))^3+3e^{-2x}(\log(\ln x))^2(\log(\ln x))'$

$=-2e^{-2x}(\log(\ln x))^3+3e^{-2x}(\log(\ln x))^2\dfrac{(\ln x)'}{\ln10\,\ln x}$

$=-2e^{-2x}(\log(\ln x))^3+\dfrac{3e^{-2x}(\log(\ln x))^2}{\ln10\,x\ln x}$

(3)

$\left(\sin(xe^x)^3\right)'=\left(\sin(x^3e^{3x})\right)'=\cos(x^3e^{3x}(x^3e^{3x})'$

$=\cos(x^3e^{3x})((x^3)'e^{3x}+x^3(e^{3x})')$

$=\cos(x^3e^{3x})(3x^2e^{3x}+3x^3e^{3x})$

$=3x^2e^{3x}(1+x)\cos(x^3e^{3x})$

(4)

$\left(\sin^3(xe^x)\right)'=3\sin^2(xe^x)\left(\sin(xe^x)\right)'$

$=3\sin^2(xe^x)\cos(xe^x)(xe^x)'$

$=3\sin^2(xe^x)\cos(xe^x)(x'e^x+x(e^x)')$

$=3\sin^2(xe^x)\cos(xe^x)(e^x+xe^x)$

$=3e^x(1+x)\sin^2(xe^x)\cos(xe^x)$

(5) Use implicit differentiation here.

$(\ln(xy))'=(e^{2y})'$

$\dfrac{(xy)'}{xy}=2e^{2y}y'$

$\dfrac{x'y+xy'}{xy}=2e^{2y}y'$

$y+xy'=2xye^{2y}y'$

$y=(2xye^{2y}-x)y'$

$y'=\dfrac y{2xye^{2y}-x}$

8 0

3 years ago

Can someone help me on this with the steps? thanks!

soldi70 [24.7K]

Answer:

8h + 15 = 39

Step-by-step explanation:

The base fee is 15 so you shouldn't multiply the hours by it.

The question states 8 per hour which means that you should multiply the 8 by hours and add on the base fee which is 15.

8 0

3 years ago

Read 2 more answers

the length of a train car is 50.6 feet. this is 5.8 feet less than 6 times the width . what is the width?

Arisa [49]

Answer:

56.4

Step-by-step explanation:

3 0

3 years ago

Albert drew a rectangular prism with the following dimensions:

raketka [301]

The volume of the rectangular prism that Albert drew given its dimensions is 576 inches³.

<h3>What is the volume?</h3>

A rectangular prism is a three-dimensional object that is made up of six faces, 12 sides and 6 vertices. The volume of the rectangular prism can be determined by multiplying the dimensions of the figure together.

Volume = length x width x height

8 x 6 x 12 = 576 inches³

To learn more about rectangular prisms, please check: brainly.com/question/8890358

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7 0

2 years ago