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1 year ago

HELPP ME PLEASEEE I WILL GIVE BRAINLEST

Mathematics

2 answers:

Shtirlitz [24]1 year ago

8 0

Answer:

5.7 is the answer I had the same question in my test

erik [133]1 year ago

7 0

Answer: 171/4, and 14.25

Step-by-step explanation:

We can solve this by first finding the area of each piece of fabric. Area is width multiplied by height, so:

3 * (4+3/4) = 57/4

We can multiply our answer by 3 again to find the total area.

57/4 * 3 = 171/4

To find the fabric as a decimal, we can first put it as a mixed fraction

$14\frac{1}{4}$

This becomes 14.25

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2 years ago

How do you write the point slope form of a linear equation?

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3 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

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3 years ago