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True [87]
3 years ago
12

PLEASE SOMEONE HELP ME FIND THE AMOUNT

Mathematics
1 answer:
Naily [24]3 years ago
6 0

Answer:

<u>$1248</u>

Step-by-step explanation:

I = 960 x 3 x 0.1

= 2880 x 0.1

= $288

<u>Amount </u>

= 960 + 288

= <u>$1248</u>

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A vending machine automatically pours soft drinks into cups. The amount of soft drink dispensed into a cup is normally distribut
labwork [276]

Answer:

a) P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-7.6}{0.4})=P(Z>1)

And we can find this probability using the complement rule and the standard normal table or excel:

P(Z>1)=1-P(Z

b)P(X

And we can find this probability using the standard normal table or excel:

P(Z

c) For this case we have a total of 868 cups and we know that the fraction of cups that will be overflow is 0.159, so then the expected number of cups overflow would be:

N = 868*0.159= 138.012 \approx 138

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the amount of soft frink of a population, and for this case we know the distribution for X is given by:

X \sim N(7.6,0.4)  

Where \mu=7.6 and \sigma=0.4

We are interested on this probability

P(X>8)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-7.6}{0.4})=P(Z>1)

And we can find this probability using the complement rule and the standard normal table or excel:

P(Z>1)=1-P(Z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the standard normal table or excel:

P(Z

Part c

For this case we have a total of 868 cups and we know that the fraction of cups that will be overflow is 0.159, so then the expected number of cups overflow would be:

N = 868*0.159= 138.012 \approx 138

6 0
4 years ago
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