Given: k= midpoint
hk=x+6
hj=4x-6
Remember midpoint cuts the segment hj in equal parts that means hk=kj and hk+kj=hj
hk+hk=hj
2hk=hj
2hk=hj
2 (x+6)=(4x-6)
2x+12=4x-6
2x-2x+12=4x-2x-6
12=2x-6
12+6=2x-6+6
18=2x
18/2=2x/2
9=x
hk=kj=x+6=(9)+6=15
kj=15
Solution :
Given that :
The radius of circle A = 6 cm
The radius of circle C = 4 cm
In circle A
The length of arc EF = 
= 14.653 cm
In circle C
The length of arc GH =
= 9.769 cm
Therefore,
The length of EF is 14.653 cm
The length of GH is 9.769 cm
The length of EF is 1.5 times the length of GH
i.e. 14.653 = 1.5 x 9.769
14.653 = 14.653
Hence proved.
To add decimals, line up the decimal points.
Here are some examples.
1.2
1.43
10.2
2.5
938.290
21.001
After you line up the decimal points, just add and carry down the decimal point.
14.37
5.63
_____
20.00
So, the answer is 20.
Answer:
8 mi³
Step-by-step explanation:
area of base=1/2×3×4=6 mi²
volume =1/3×base area×height
=1/3×6×4
=8 mi³
Probably the easiest way to do these is to convert them to slope intercept form by solving for y. When we have y=mx+b, we read off the slope m.
-5x + 2y = 10
Add 5x to both sides,
2y = 5x + 10
Divide both sides by 2,
y = (5/2) x + (10/2)
Obviously 10/2=5 but we don't care about that for this problem. We read off the slope as
Answer: 5/2, last choice
12 = 4x - 6y
Adding 6y and subtracting 12,
6y = 4x - 12
Dividing by 6,
y = (4/6) x - (12/6)
y = (2/3) x - 2
Answer: 2/3
