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2 years ago

6

We can think of the division expression 10 divided by 2 1/2 as the answer to the question “how many groups of 2 1/2 are in 10 an

d explain your answer

1 answer:

mrs_skeptik [129]2 years ago

8 0

Answer:

<em>4 Groups</em>

Step-by-step explanation:

2 1/2 can be written as 2.5, and since this is division, all we have to do is divide 10 by 2.5.

10/2.5=4

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Devin has a snake. The snake eats one mouse every week which Devin purchases from the local pet store. If m represents the cost

n200080 [17]

Assuming it's not a leap year,
then there are 365 days a year.
This is about 52 weeks.
The cost of a mouse is 52m

4 0

3 years ago

The points (-10, 0) and (-5, 3) fall on a particular line. What is it’s equation in slope-intercept form?

yaroslaw [1]

Answer:

y = 3/5x + 6

Step-by-step explanation:

When given two points, it is convenient to start with the 2-point form of the equation of a line, then rearrange it to the form needed for the problem. For points (x1, y1) and (x2, y2), the equation is ...

y = (y2 -y1)/(x2 -x1)·(x -x1) +y1

Filling in the given point coordinates, this is ...

y = (3 -0)/(-5 -(-10))·(x -(-10)) + 0

y = 3/5(x +10)

y = (3/5)x + 6

5 0

3 years ago

The lakeside marina charges a $35 rental fee for a boat in addition to charging $15 per hour. Part D:what information does the i

STALIN [3.7K]

Answer: B.The cost of rental fee only

Step-by-step explanation:

The $35 is the cost of the rental fee only. The person would then have to pay a further $15 for every hour they use the boat.

Essentially, the $35 is the fixed cost associated with the rental and the $15 is the variable cost to do so. If this were in a linear equation format it would take the form: y = 15x + 35.

7 0

2 years ago

A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq

oksano4ka [1.4K]

Answer:

$Lower = 231.134- 3.098=228.036$

$Upper = 231.134+ 3.098=234.232$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case we know that the 95% confidence interval is given by:

$\bar X=\frac{233.002 +229.266}{2}= 231.134$

And the margin of error is given by:

$ME = \frac{233.002 -229.266}{2}= 1.868$

And the margin of error is given by:

$ME= t_{\alpha/2} \frac{s}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1 = 5-1=4$

And the critical value for 95% of confidence is $t_{\alpha/2}= 2.776$

So then we can find the deviation like this:

$s = \frac{ME \sqrt{n}}{t_{\alpha/2}}$

$s = \frac{1.868* \sqrt{5}}{2.776}= 1.506$

And for the 99% confidence the critical value is: $t_{\alpha/2}= 4.604$

And the margin of error would be:

$ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098$

And the interval is given by:

$Lower = 231.134- 3.098=228.036$

$Upper = 231.134+ 3.098=234.232$

6 0

3 years ago

Are you able to write?

Volgvan

Answer:

Well isn't anyone able to write?

3 0

3 years ago

Read 2 more answers