Answer:
1)28.8%
2)28.8%
3)43.6%
Step-by-step explanation:
1))Probability of wining both = Probability that first contract is won* Probability that second contract is won = 0.4 * 0.72 = 0.288 = 28.8%
2)Probability of losing = 1 - Probability of winning
Probability that they will lose both contracts = Probability that first contract is lost * Probability that second contract is lost = (1 - 40/100) * (1 - 54/100) = 0.276 = 27.6%
3)Probability that any one is won = 1 - both contracts are won - both contracts are lost = 1 - 0.276 - 0.288 = 0.436 = 43.6%
Answer:
Step-by-step explanation:
x³-6x²+11x-6
put x=1
1³-6×1²+11×1-6=1-6=11-6=0
by synthetic division
1| 1 -6 11 -6
| 1 -5 6
|----------------
| 1 -5 6 |0
x²-5x+6=0
x²-2x-3x+6=0
x(x-2)-3(x-2)=0
(x-2)(x-3)=0
x=1
x-1=0
so x³-6x²+11x-6=(x-1)(x-2)(x-3)
Answer:
Enjoy, Glad i could help
Step-by-step explanation:
Answer:
Step-by-step explanation:
Collect like terms
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Calculate
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Hope I helped!
Best regards! :D
Answer:
Step-by-step explanation:
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