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nataly862011 [7]
2 years ago
10

Refer to the technology output given to the right that results from measured hemoglobin levels (g/dL) in 100 randomly selected a

dult females. The Tntrval confidence level of 90% was used. 13.032,13.418) x= 13.225 a. Express the confidence interval in the format that uses the "less than" symbol. Assume that the original listed data use two decimal places, andSx-1.164 round the confidence interval limits accordingly. b. Identify the best point estimate of μ and the margin of error. c. In constructing the confidence interval estimate of μ, why is it not necessary to confirm that the sample data appear to be from a population with a normal distribution?
Mathematics
1 answer:
charle [14.2K]2 years ago
8 0

Answer:

Step-by-step explanation:

a)

Confidence interval in less than symbol expressed as

\bar{x} - E < \mu < \bar{x} + E&#10;

Where \bar{x} is sample mean and  E is margin of error.

13.03 < \mu 13.42&#10;

b)

The given t interval is (13.032 , 13.418 )&#10;

That is \bar{x} - E = 13.032 and \bar{x} + E = 13.418

Solve these two equation by adding together.

2 \bar{x} = 13.032 + 13.418&#10;\\\\\bar{x} = 13.225

Solve this value of \bar{x} in equation \bar{x} - E = 13.032 and solve for E

13.225 - E = 13.032&#10;\\\\E = 0.193&#10;

Best point estimate of \mu = \bar{x} = 13.225&#10;

Best point estimate of margin of error = 0.193

c)

Since sample size = 100 which is sufficiently large (Greater than 30) , it is no need to confirm that

sample data appear to be form a population with normal distribution.

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