log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
brainly.com/question/16845433
#SPJ1
Answer:The slope is defined as the ratio of the vertical change between two points, the rise, to the horizontal change between the same two points, the run. The slope of a line is usually represented by the letter m. (x1, y1) represents the first point whereas (x2, y2) represents the second point.
Answer:
Step-by-step explanation:
If a point (x, y) lies on a straight line, coordinates of the point will satisfy the equation.
Slope of a line passing through two points C(4, 5) and D(8, 10),
m =
m =
m =
Equation of the line passing through C(4, 5) and slope m =
y - y' = m(x - x')
y - 5 =
y =
y =
If point B(4, 0) lies on the line CD,
0 =
0 = 5
Which is not true.
Therefore, point B doesn't lie on line CD.
(a + b)^3 = a^3 + 3a^2b + 3ab^2+ b^3
(a +(- b))^3 = (a-b)^2 = a^3 - 3a^2b + 3ab^2- b^3