Solving for the polynomial function of least degree with
integral coefficients whose zeros are -5, 3i
We have:
x = -5
Then x + 5 = 0
Therefore one of the factors of the polynomial function is
(x + 5)
Also, we have:
x = 3i
Which can be rewritten as:
x = Sqrt(-9)
Square both sides of the equation:
x^2 = -9
x^2 + 9 = 0
Therefore one of the factors of the polynomial function is (x^2
+ 9)
The polynomial function has factors: (x + 5)(x^2 + 9)
= x(x^2 + 9) + 5(x^2 + 9)
= x^3 + 9x + 5x^2 = 45
Therefore, x^3 + 5x^2 + 9x – 45 = 0
f(x) = x^3 + 5x^2 + 9x – 45
The polynomial function of least degree with integral coefficients
that has the given zeros, -5, 3i is f(x) = x^3 + 5x^2 + 9x – 45
9514 1404 393
Answer:
120 m²
Step-by-step explanation:
If you divide the isosceles triangle into two right triangles, each has a leg and hypotenuse of 8 and 17, respectively. You may recognize these numbers as part of the Pythagorean triple (8, 15, 17). That recognition tells you the triangle's height is 15 m, so its area is ...
A = 1/2bh
A = 1/2(16 m)(15 m) = 120 m² . . . . triangle area
__
<em>Alternate solutions</em>
Given the three sides, you can find the smallest angle from the Law of Cosines. It will be ...
α = arccos((17² +17² -16²)/(2·17·17)) ≈ 56.144°
Then the area is ...
A = 1/2·ab·sin(C) . . . for triangle with sides a, b, c and opposite angles A, B, C
A = 1/2sin(α)·17·17 = 120 . . . m²
__
Using Heron's formula:
s = (17 +17 +16)/2 = 25
A = √(25(25 -17)(25 -17)(25 -16)) = 5×8×3 = 120 . . . m²
__
If you need to, you can compute the triangle's height from the Pythagorean theorem.
a² +b² = c² . . . . generic Pythagorean theorem equation
8² + h² = 17² . . . with relevant values filled in
h² = 289 -64 = 225
h = √225 = 15
Answer:
10x^2 + 11x-6=0
Step-by-step explanation:
The complete question is
"which statement is true about the extreme value the given quadratic equation? y = -3x^2 + 12x - 33
Oa. The equation has a maximum value with a y coordinate of -27
Ob. The equation has a minimum value with a y coordinate of -21
Oc. the equation has a minimum value with a y coordinate of -27
Od. The equation has a maximum value with a y coordinate of -21"
The quadratic equation has the extreme value at the vertex with a y-coordinate of -21. so, the correct option is D.
<h3>What is a quadratic equation?</h3>
A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
The given quadratic equation is
y=-3x^2+12x-33
x = -b/2a
For the given equation the vertex :
x = -12/2(-3) = 2
The value of y at x = 2 is:
y = -3(2²) + 12(2) - 33
y = -12 + 24 - 33
y = -21
The extreme is the maximum for the given equation.
The correct choice is D.
Learn more about quadratic equations;
brainly.com/question/13197897
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Answer:
the branch of mathematics dealing with the relations of the sides and angles of triangles and with the relevant functions of any angles.
Step-by-step explanation:
