2 years ago

Points for whoever wants them sjakakakkaai

1 answer:

6 0

Answer:

thank you!!! hope you have a great day! :)

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Alina [70]

The is 42 because that the answer to the question

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2 years ago

Rudiy27

Answer: $\bold{D.\ \dfrac{x+4}{x}\ where\ x \neq 0, \dfrac{2}{3}}$

<u>Step-by-step explanation:</u>

f(x) = 3x² + 10x - 8

g(x) = 3x² - 2x

$\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}$

Restriction on x: the denominator cannot be equal to zero. So,

x(3x - 2) ≠ 0

→ x ≠ 0 and 3x - 2 ≠ 0

3x ≠ 2

x $\neq \dfrac{2}{3}$

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3 years ago

Leni [432]

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3 years ago

alex41 [277]

Use photo math it will help

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3 years ago

mart [117]

Answer:

3x + 9 + 4x + x = 8x + 9

Step-by-step explanation:

combine like terms

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3 years ago