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natima [27]
2 years ago
5

Points for whoever wants them sjakakakkaai

Mathematics
1 answer:
const2013 [10]2 years ago
6 0

Answer:

thank you!!! hope you have a great day! :)

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A pole that is 2.7 m tall casts a shadow that is 1.76 m long. At the same time, a nearby building casts a shadow that is 44.25 m
natali 33 [55]

Answer:

81

Step-by-step explanation:

9x9

2x2

5 0
3 years ago
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Rainbow [258]

Answer:

p + q = -6

Step-by-step explanation:

p^{2} + 6 p = q^{2} + 6q \\p^{2} - q^{2} = 6q - 6p

( p + q) ( p-q) = 6 ( q - p )

p + q = \frac{6 ( q - p)}{(p-q)}  \\p + q = \frac{-6( p - q)}{(p - q)} \\p + q = -6

5 0
2 years ago
How do I describe the real zeroes of this function using Descartes's Rule of Signs?
Serhud [2]
The number of positive roots is the number of changes of signs there are, then decrease by 2 each time and stop when you get to 1 or 0

negative roots, sub every x with -x and reevaluate, count change of signs
decrease by 2 each time and stop when you get to 1 or 0

y=+2x⁵-x⁴-2x³+4x²+x-2
+,-,-,+,+,-
 1    2  3

3 or 1 positive roots

replace x with -x ( baically flip all signs of odd powerd numbers)

y=-2x⁵-x⁴+2x³+4x²-x-2
   -,-,+,+,-,-
     1    2

2 or 0 negative roots



3 or 1 positive roots
2 or 0 negative roots
2nd option is answer

4 0
3 years ago
Mm
Novay_Z [31]

Answer:

x + 2(2x-4) = 10

Step-by-step explanation:

Here in this question, we want to select which is the correct answer if we substitute for the value of y in the second equation, using the first.

In the first, we have;

y = 2x -4

Now, let’s input this value of y into the second equation.

By direct substitution, what we have is the following;

x + 2y = 10

—-> x + 2(2x -4) = 10

8 0
3 years ago
The graph of
ratelena [41]

Answer:

Positive and negative intervals on a graph

Step-by-step explanation:

The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero). The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero). hope this helps you :)

3 0
3 years ago
Read 2 more answers
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