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2 years ago

15

Half of the class scored above 78% and half of the class

2 answers:

andrey2020 [161]2 years ago

7 0

Answer:

Median

Step-by-step explanation:

zlopas [31]2 years ago

5 0

Answer:

78% is the median

Step-by-step explanation:

The median is the middle number in a sorted, ascending or descending, list of numbers

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Patricia tiene $80.000 sólo en billetes de $5.000, Camila tiene $60.000 sólo en billetes de $2.000 y Andrea tiene $120.000 sólo

soldier1979 [14.2K]

Answer:

mmmm

Step-by-step explanation:

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3 years ago

Which segments are parallel?

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2 years ago

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Margo borrows $500, agreeing to pay it back with 3% annual interest after 14

Akimi4 [234]

Answer:

$\$17.50$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest to pay

P is the amount of money borrowed

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=\frac{14}{12}\ years\\ P=\$500\\r=3\%=3/100=0.03$

substitute in the formula above

$I=500(0.03)(\frac{14}{12})$

$I=\$17.50$

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3 years ago

A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d fro

Mrac [35]

Answer:

The equation of the displacement $d$ as a function of time $t$ is :

$d(t)=8sin(\pi t+\pi )$

Step-by-step explanation:

Generally , A simple harmonic wave is a sinusoidal function that is it can be expressed in simple $sin$ or $cos$ terms.

Thus,

$d(t) = Asin(wt+c)$

is the general form of displacement of a SHM.

where,

<em> $d(t)$ is the displacement with respect to the mean position at any time $t$ </em>
<em> $A$ is amplitude </em>
<em> $w$ is the natural frequency of oscillation ( $rads^{-1}$ )</em>
<em> $c$ is the phase angle which indicates the initial position of the object in SHM ( $rad$ )</em>

given,

Time period ( $T$ ) = $2s$
$A=8$
The natural frequency ( $w$ ) and time period ( $T$ ) is :

$w=\frac{2\pi} {T}$

∴

$w$ = $\frac{2\pi }{2} = \pi$ $rads^{-1}$

∴

the equation :

<em>⇒ $d(t)=8sin(\pi t+c)$ </em> ------1

since $d=0$ when $t=o$ ,

<em>⇒ $0=8sinc\\c=n\pi$ ------2</em>

where n is an integer ;

<u>⇒since the bouy immediately moves in the negative direction , $x$ must be negative or c must be an odd multiple of $\pi$ .</u>

<em>⇒ $d(t) = 8sin(\pi t+(2k+1)\pi )$ ------3</em>

where k is also an integer ;

the least value of $k=0$ ;

thus ,

the equation is :

$d(t)=8sin(\pi t+\pi )$

<em></em>

7 0

2 years ago

What is the simpler form of (6 + m^2) (6 -m^2)

PtichkaEL [24]

Answer:

=36-m^4

Step-by-step explanation:

8 0

2 years ago