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faltersainse [42]
2 years ago
7

Find the area of the shaded reg

Mathematics
1 answer:
Neporo4naja [7]2 years ago
4 0

Answer:

C DJ DJ DJ DJ to Yoo to dh DJ SF at cb CJ Yoo op BN CNN DJ DJ DJ Yoo DJ DJ go

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Solve the equation <br> 5(x+4)+52= -4x
Maru [420]

Answer:

x = -8

Step-by-step explanation:

Given: 5(x+4)+52=-4x

Distributive Property: 5x+20+52=-4x

Combine like terms: 5x+72=-4x

Subtract 5x on both sides: 72=-9x

Divide both sides by -9: -8=x

Flip the equation around: x=-8

Therefore, x=-8

8 0
2 years ago
Find the vertical component given that R = 42 lb. and = 80.<br><br> 41.36<br> 7.29<br> 59.45
valentina_108 [34]

Answer:

a

Step-by-step explanation:

3 0
2 years ago
Find the equations of the tangent lines to x2+y2=1 at x=0, x=1 and x=35.
Ivanshal [37]
Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].

So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).

There is one tangent at x = 1. It is x = 1 (a vertical line).

There is no tangent at x = 35, because the original equation has no solution at x = 35.
4 0
3 years ago
Please help asap! :’)
Alina [70]

Answer:

4ba\root(3)(b^(2))

or

4ba\sqrt[3]{b^2}

6 0
3 years ago
A ship leaves port and travels due west for 30 knots, then changes course to S 30° W and travels 50 more knots. Find the bearing
leva [86]

Answer:

  232°

Step-by-step explanation:

There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.

  30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))

  = (0, -30) +(-43.301, -25) = (-43.301, -55)

Then the angle from port is ...

  arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle

The bearing of the ship from port is about 232°.

_____

<em>Comment on the problem statement</em>

The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.

5 0
3 years ago
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