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4 years ago

Is 14 quarter inches the most common measurement

Mathematics

1 answer:

borishaifa [10]4 years ago

7 0

^ if you're talking universally, no it would be cm. But no one really says "quarter inches". You would just say inches

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Find the x and y intercept and the slope of the graph of 8x-6y=24

andreev551 [17]

Answer:

the x intersept is 3 the y intercept is 4

Step-by-step explanation:

x intersept : 24/8 = 3

y intersept : 24/6 =4

4 0

3 years ago

Multiple the binomials (x+3)^2

maxonik [38]

Answer:

$=x^2+6x+9$

Step-by-step explanation:

$\left(x+3\right)^2\\\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2\\a=x,\:\:b=3\\=x^2+2x\cdot \:3+3^2\\\mathrm{Simplify}\:x^2+2x\cdot \:3+3^2:\quad x^2+6x+9\\x^2+2x\cdot \:3+3^2\\\mathrm{Multiply\:the\:num\\bers:}\:2\cdot \:3=6\\=x^2+6x+3^2\\3^2=9\\=x^2+6x+9$

8 0

3 years ago

Evaluate the line integral c y3 ds,<br> c.x = t3, y = t, 0 â‰¤ t â‰¤ 3

Temka [501]

$\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\int_{t=0}^{t=3}t^3\sqrt{1^2+(3t^2)^2}\,\mathrm dt=\int_0^3t^3\sqrt{1+9t^4}\,\mathrm dt$

Take $u=1+9t^4$ so that $\mathrm du=36t^3\,\mathrm dt$ . Then

$\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\frac1{36}\int_{u=1}^{u=730}\sqrt u\,\mathrm du=\frac{730^{3/2}-1}{54}$

7 0

3 years ago

PLEASE HELP!! I WILL BRAINLIEST

ArbitrLikvidat [17]

Answer:

81.8%

Step-by-step explanation:

Mean = $\mu = 40$

Standard deviation = $\sigma = 5$

Now we are supposed to find out what percent of the numbers fall between 35 and 50

$z = \frac{x-\mu}{\sigma}$

Substitute the values

$z = \frac{x-40}{5}$

Now for P(35<x<50)

Substitute x = 35

$z = \frac{35-40}{5}$

$z =-1$

Substitute x = 50

$z = \frac{50-40}{5}$

$z =2$

So, P(-1<z<2)

P(z<2)-P(z<-1)

=0.9772-0.1587

=0.8185

= $0.818 \times 100$

=81.8%

Hence 81.8% percent of the numbers fall between 35 and 50

7 0

3 years ago

A baker recorded the number of batches of

azamat

Answer:

B. The lower extreme increased.

Step-by-step explanation:

From the original box and whisker plot, the lower extreme (minimum) is 5 ; The upper extreme, maximum is 15.

The number of batches baked on the eight day is 20. This exceeds tbe previous maximum value. Hence, upper extreme( maximum) value of the new plot will change from 15 to 20.

The lower extreme isn't affected as the obtained value isn't below 5.

The median value will Increase and the upper quartile value will also increase. Once the upper quartile value increases, the interquartile range will also increase

6 0

3 years ago