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2 years ago

Hi, I can use some help wiTh this thanks!

Mathematics

2 answers:

Digiron [165]2 years ago

8 0

The square root of 9 is three because 3 to the power of two, or three squared is 9

Vladimir79 [104]2 years ago

7 0

Answer:

Square root of 9 = 3 ! ^^

Step-by-step explanation:

$3*3=9 \\3^{2}=9\\\sqrt{9} = 3$

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HELP PLS! I WILL CHOOSE BRAINLIEST!

inn [45]

awnser: .

explanation:

5 0

3 years ago

Read 2 more answers

A certain type of thread is manufactured with a mean tensile strength of 78.3 kilograms and a standard deviation of 5.6 kilogram

azamat

Answer:

(a) The variance decreases.

(b) The variance increases.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The standard deviation of sample mean is inversely proportional to the sample size, n.

So, if n increases then the standard deviation will decrease and vice-versa.

(a)

The sample size is increased from 64 to 196.

As mentioned above, if the sample size is increased then the standard deviation will decrease.

So, on increasing the value of n from 64 to 196, the standard deviation of the sample mean will decrease.

The standard deviation of the sample mean for n = 64 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{64}}=0.7$

The standard deviation of the sample mean for n = 196 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4$

The standard deviation of the sample mean decreased from 0.7 to 0.4 when n is increased from 64 to 196.

Hence, the variance also decreases.

(b)

If the sample size is decreased then the standard deviation will increase.

So, on decreasing the value of n from 784 to 49, the standard deviation of the sample mean will increase.

The standard deviation of the sample mean for n = 784 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{784}}=0.2$

The standard deviation of the sample mean for n = 49 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{49}}=0.8$

The standard deviation of the sample mean increased from 0.2 to 0.8 when n is decreased from 784 to 49.

Hence, the variance also increases.

6 0

3 years ago

The minimum value of 2x + 1 is 13

Tamiku [17]

Hi Jalansmith133!

$
2x+1 = 13 \\ \\
2x = 12 \\ \\
x = 6
$

GoodLuck...

8 0

3 years ago

A line segment with endpoints A(−2, 1) and B(2, 1) is dilated with a dilation centered at the origin and a scale factor of 52 to

igomit [66]

Answer:

AB = 5/2 A'B'

Step-by-step explanation:

the other answers:

2) (−1, 3/2)

3) 8 inches

4) The scale factor is between 0 and 1

5) (8, −4) and (−4, −12)

I just took the quick check, these are the answers. I know you already took it so this isn't helpful but if anyone else needs it^^

3 0

3 years ago

A business is using two painters to paint 3 offices, each with 1,200 square feet of wall space. one painter can paint 190 square

ivann1987 [24]

To determine the total time it needs for the two painters to completely paint the whole wall space, we need to relate the total area of the wall to be painted and the time they need. So, base from the problem, the relation would just be a linear function. We do as follows:

let A = total area of the wall space
t = total time they both need

Painter 1 = 190 square feet per hour
Painter 2 = 130 square feet per hour
total area = 1200 ft^2 (3) = 3600 ft^2

The function would be:

A = 190t + 130t
3600 = 190t + 130t
3600 = 320t
t = 11.25 hrs

5 0

4 years ago