Answer:
x = -1
Step-by-step explanation:
2(x – 2) + 6 = 0
~Distribute left side
2x - 4 + 6 = 0
~Combine like terms
2x + 2 = 0
~Subtract 2 to both sides
2x = -2
~Divide 2 to both sides
x = -1
Best of Luck!
freezing point. 32 or below is freezing point.
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
k =4
Step-by-step explanation:
5k-2k=12
Combine like terms
3k = 12
Divide each side by 3
3k/3 = 12/3
k = 4
