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1 year ago

Which expression is equivalent to -6x + 7.5?

Mathematics

2 answers:

Grace [21]1 year ago

5 0

Answer:

[A] -3(2x-2.5)

Step-by-step explanation:

<em>Given:</em>

<em>Which expression is equivalent to -6x + 7.5?</em>

<em>Solution:
Going through all answer choices:</em>

<em>Simplify</em>

<em />

<em>Simplify</em>

<em />

<em>Simplify</em>

<em />

<em>Simplify</em>

<em />

<em>Hence, the answer is [A] -3(2x-2.5)</em>

<em />

<u><em>Kavinsky</em></u>

<em />

Neporo4naja [7]1 year ago

4 0

<h2>Hey there!</h2>

<h3>The expression which is equivalent to - 6x + 7.5 is option (A) - 3(2x - 2.5).</h3>

<h3>☆Explanation:</h3>

- 6x + 7.5

If you we split this equation then we'll get -3(2x-2.5).

Because,

- 3 × 2x gives -6x
(-3) × - 2.5 gives + 7.5

<h2>Hope it helps </h2>

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The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\$

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>