Answer:
Here is a graph of that equation.
Let me know if you need more help! :)
Answer:
Step-by-step explanation:
The mean SAT score is
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it
) is

Next they draw a random sample of n=70 students, and they got a mean score (denoted by
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
Answer:
Restaurant A: 31 grams of fat
Restaurant B: 25 grams of fat
Step-by-step explanation:

Multiply 2 by 10, divide the answer by 5, and add 3 to the final answer
Answer:
The answer would be 11.51
Step-by-step explanation:
π is rougroughly 3.14
√70 = 8.37
3.14 + 8.37 = 11.51