Answer:
The concentration of the NaOH solution CB = 0.251 M
Explanation:
The balanced equation of reaction is:
H2SO4 + 2NaOH ===> Na2SO4 + 2H2O
Using titration equation of formula
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)
NB is the number of mole of base = 2 (from the balanced equation of reaction)
CA is the concentration of acid = 0.1053 M
CB is the concentration of base = to be calculated
VA is the volume of acid = 17.88 mL
VB is the volume of base = 15.00mL
Substituting
0.1053×17.88/CB×15 = 1/2
Therefore CB =0.1053×17.88×2/15×1
CB= 0.251 M
Isotopes are defined as atoms of same element with different mass number and same atomic number.
Here, atomic number is equal to number of protons and number of electrons, it is denoted by symbol Z thus,
and, mass number is equal to sum of number of protons and neutrons, it is denoted by symbol A thus,
The three isotopes of tin are given, Sn-116, Sn-120 and Sn-126, mass number for these three isotopes is 116, 120 and 126 respectively. Since, they are isotopes thus, atomic number remains the same that is 50.
Since, thus, number of protons and electrons will be 50.
For Sn-116,
Or,
Or,
For Sn-120,
For Sn-126,
Therefore, mass number, number of protons, electrons and neutrons in all three isotopes are:
Sn-116:
Mass number= 116
Protons=50
neutrons=66
electrons=50
Sn-120:
Protons=50
neutrons=70
electrons=50
Sn-126:
Protons=50
neutrons=76
electrons=50
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Answer:
use this formula it will help u .
Explanation:
If 60 ml of ethanol is diluted to a final volume of 400 ml, you create a 35 % ethanol solution.
First, realize that you creating a solution with that contains a polar solute (ethanol) with a polar solvent (water). Remember that "like dissolves like."
If you pour 60 ml of ethanol in a volumetric flask, you add 340 ml of water to dilute this solution to a final volume of 400 ml.
Volumetric flasks are designed to make or dilute solutions to specified final volume.
Since you have 60 ml of ethanol in a total solution of 400 ml, the percentage of ethanol is 35 %.
This result is obtained in the following manner.
ml/400. ml. = .35
.35 x 100% = 35 %
