Answer:
Cs > Ba > Bi > Hf > Ta
Explanation:
The atomic radius of a chemical element defined as the distance between nucleus and electron from the center.
<u>The atomic number and atomic radius of given elements are:</u>
<u>Barium (Ba):</u>
Atomic number - (56)
Atomic radius - 268 pm
<u>Caesium (Cs) </u>
Atomic number - 55
Atomic radius - 343 pm
<u>Hafnium (Hf):</u>
Atomic number - 72
Atomic radius - 225 pm
<u>Bismuth (Bi):</u>
Atomic number - 83
Atomic radius - 230
<u>Tantalum (Ta):</u>
Atomic number - 73
Atomic radius - 220 pm
According to the given atomic radius the decreasing order of atomic radius is Cs > Ba > Bi > Hf > Ta.
Caesium has highest atomic radius among all even though lowest atomic number because the force of attraction between the nucleus and the outermost electron is low and outermost electron are loosely held.
Barium (Ba) has lower atomic number than Bismuth (Bi) but still atomic radius of Barium is high because moving across the periodic table atomic radius decreases as force of attraction between nucleus and outer electrons is high.
Bismuth (Bi) has higher atomic number that Hafnium (Hf), atomic radius of Bi is more than Hf.
Tantalum (Ta) have higher atomic number than Hafnium (Hf) but still have lower atomic radius as as force of attraction between nucleus and outer electrons is high.
Hence, the decreasing atomic radius is Cs > Ba > Bi > Hf > Ta.
Answer:
B. They all have molecules in motion.
Explanation:
All substances have molecules in motion, this is because all substances have an average kinetic energy (temperature) of over 0 K.
Answer:
Explanation:
Hello,
In this case, considering the Arrhenius law, the decreasing ratio is:
By considering the 115°C as 1 and 230°C as 2, we obtain:
And the increasing ratio:
Best regards.
Answer:
<h3>B.) Can(S) + 02(g)</h3>
Explanation:
I hope it helps :)
Answer:
Explanation:
The volume and amount of gas are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.
Data:
p₁ =5.7 atm; T₁ = 100.0 °C
p₂ = ?; T₂ = 20.0 °C
Calculations:
1. Convert the temperatures to kelvins
T₁ = (100.0 + 273.15) K = 373.15
T₂ = (20.0 + 273.15) K = 293.15
2. Calculate the new pressure